Question

我只是使用CodeBlocks在C语言中构建一个简单的计算器。构建并运行它之后，它一直运行到scanf（）语句为止。在我输入2个数字供我的程序扫描并点击输入后，程序崩溃并发送了一条消息“ C.exe已停止工作。”请帮助。这是代码-

#include <stdio.h>
#include <stdlib.h>

int Calculator();

int main()
{
    Calculator();
    return 7;
}

int Calculator()
{
    int num1;
    int num2;
    int operation;

    printf("Hello. I am a calculator.\nChoose any operation you want to carry out- \n 1.Addition \n 2.Subtraction \n 3.Multiplication \n 4.Division \n");
    scanf("%d", &operation);

    switch (operation)
    {
        case 1:
            printf("OK. You have chosen addition. \nEnter any 2 numbers to be added \n");
            scanf("%d", num1);
            scanf("%d", num2);
            printf("%d + %d is = %d. \n Thank you. ", num1, num2, num1 + num2);
            break;

        case 2:
            printf("OK. You have chosen subtraction. \nEnter any 2 numbers to be subtracted \n");
            scanf("%d", num1);
            scanf("%d", num2);
            printf("%d - %d is = %d. \n Thank you. ", num1, num2, num1 - num2);
            break;

        case 3:
            printf("OK. You have chosen multiplication. \nEnter any 2 numbers to be multiplied \n");
            scanf("%d", num1);
            scanf("%d", num2);
            printf("%d x %d is = %d. \n Thank you. ", num1, num2, num1 * num2);
            break;

        case 4:
            printf("OK. You have chosen division. \nEnter any 2 numbers to be divided \n");
            scanf("%d", num1);
            scanf("%d", num2);
            printf("%d ÷ %d is = %d. \n Thank you. ", num1, num2, num1 / num2);
            break;

        default:
            printf("\nHUH?\n\n");
            break;
    }
    return 20;
}

Answer 1

您在scanf内部进行的switch呼叫是错误的。您需要&。

更改：

scanf("%d", num1);
scanf("%d", num2);

至：

scanf("%d", &num1);
scanf("%d", &num2);

我建议您检查scanf的返回。

尝试了解这一点：

#include <stdio.h>
#include <stdlib.h>

int Calculator( void );

int main( void )
{
    Calculator();
}

int Calculator( void )
{
    int num1;
    int num2;
    int operation;

    printf("Hello. I am a calculator.\nChoose any operation you want to carry out- \n 1.Addition \n 2.Subtraction \n 3.Multiplication \n 4.Division \n");
    if ( scanf("%d", &operation) != 1 ){
        printf( "Error scanf() ==>> on Operation" );
        exit( 1 );
    }

    switch (operation)
    {
        case 1:
            printf("OK. You have chosen addition. \nEnter any 2 numbers to be added \n");
            if ( scanf("%d", &num1) != 1 ){
                printf( "Error scanf() ==>> switch - case 1 ==>> 1" );
                exit( 1 );
            }
            if ( scanf("%d", &num2) != 1 ){
                printf( "Error scanf() ==>> switch - case 1 ==>> 2" );
                exit( 1 );
            }
            printf("%d + %d is = %d. \n Thank you. ", num1, num2, num1 + num2);
            break;

        case 2:
            printf("OK. You have chosen subtraction. \nEnter any 2 numbers to be subtracted \n");
            if ( scanf("%d", &num1) != 1 ){
                printf( "Error scanf() ==>> switch - case 2 ==>> 1" );
                exit( 1 );
            }
            if ( scanf("%d", &num2) != 1 ){
                printf( "Error scanf() ==>> switch - case 2 ==>> 2" );
                exit( 1 );
            }
            printf("%d - %d is = %d. \n Thank you. ", num1, num2, num1 - num2);
            break;

        case 3:
            printf("OK. You have chosen multiplication. \nEnter any 2 numbers to be multiplied \n");
            if ( scanf("%d", &num1) != 1 ){
                printf( "Error scanf() ==>> switch - case 3 ==>> 1" );
                exit( 1 );
            }
            if ( scanf("%d", &num2) != 1 ){
                printf( "Error scanf() ==>> switch - case 3 ==>> 2" );
                exit( 1 );
            }
            printf("%d x %d is = %d. \n Thank you. ", num1, num2, num1 * num2);
            break;

        case 4:
            printf("OK. You have chosen division. \nEnter any 2 numbers to be divided \n");
            if ( scanf("%d", &num1) != 1 ){
                printf( "Error scanf() ==>> switch - case 4 ==>> 1" );
                exit( 1 );
            }
            if ( scanf("%d", &num2) != 1 ){
                printf( "Error scanf() ==>> switch - case 4 ==>> 2" );
                exit( 1 );
            }
            printf("%d ÷ %d is = %d. \n Thank you. ", num1, num2, num1 / num2);
            break;

        default:
            printf("\nHUH?\n\n");
            break;
    }
    return 20;
}

您应重新考虑来自return和main的{{1}}语句

Answer 2

您要

scanf("%d", &num1);
scanf("%d", &num2);

在每个实例上。

此外，如果要防止其他崩溃，请注意除以零：）

我的程序在C中到达scanf（）语句后崩溃并停止工作

2 个答案: