我有三个表,名称为employee, employee_products, product_type
引用:http://sqlfiddle.com/#!9/00436/4
我正在尝试获取数据
将此表设为Table_1
使用此查询:
select emp.name,
(select count(*) from employee_products where product_type_id = 1 and employee_id = emp.id) as Service,
(select count(*) from employee_products where product_type_id = 2 and employee_id = emp.id) as Product,
(select count(*) from employee_products where product_type_id = 3 and employee_id = emp.id) as Other
from employee as emp;
但是,我认为效率不高,我必须从每个新的product_type_id更改此查询,然后才能动态执行此操作。
+------------+---------+---------+-------+--+
| Name | Service | Product | Other | |
+------------+---------+---------+-------+--+
| Bezos | 1 | 0 | 0 | |
+------------+---------+---------+-------+--+
| Steve | 0 | 3 | 0 | |
+------------+---------+---------+-------+--+
| Bill gates | 1 | 0 | 0 | |
+------------+---------+---------+-------+--+
| Tim Cook | 0 | 0 | 1 | |
+------------+---------+---------+-------+--+
和
将此表设为Table_2
在这种情况下,由于mysql中没有数据透视功能,因此我什至无法在mysql中做到这一点。
+------------+---------+---------+---------+---------+-----------+-------+
| Name | Amazon | iPhone | iPad | iPod | Microsoft | IDK |
+------------+---------+---------+---------+---------+-----------+-------+
| Bezos | Service | NULL | NULL | NULL | NULL | NULL |
+------------+---------+---------+---------+---------+-----------+-------+
| Steve | NULL | Product | Product | Product | NULL | NULL |
+------------+---------+---------+---------+---------+-----------+-------+
| Bill gates | NULL | NULL | NULL | NULL | PRODUCT | NULL |
+------------+---------+---------+---------+---------+-----------+-------+
| Tim Cook | NULL | NULL | NULL | NULL | NULL | OTHER |
+------------+---------+---------+---------+---------+-----------+-------+
请帮助。
注意:product_type, employee_products
表中可以有 100 个项目。
答案 0 :(得分:0)
尝试使用Table_1
Select name, Max(Service) as Service, Max(Product) as Product, Max(Other) as Other
From (
select e.name,
count(case when ep.product_type_id = 1 then 1 else null end) as Service,
count(case when ep.product_type_id = 2 then 1 else null end) as Product,
count(case when ep.product_type_id = 3 then 1 else null end) as Other,
from employee e
inner join employee_products ep on (e.id = ep.employee_id)
)
Group by name;
注意:您可以尝试使用Table_2的相同方式
答案 1 :(得分:0)
这里有几段代码可以动态生成和运行SELECT
并动态推导各列。 Here是我的。