PHP时差

Question

我在mysql中有2个日期：
2018-07-13 13:00:00-数据
2018-07-14 16:01:00-Godzina

$timestamp1 = strtotime($data['data']);<br>
$timestamp2 = strtotime($data['godzina']);<br>
$time_difference = $timestamp2 - $timestamp1; 
$time_total = ($time_difference/3600);

echo "td".$time_total."/td";

现在它返回：27.016666666667

如何将其更改为：表中的27:01？

Answer 1

您可以简单地使用DateTime->diff方法来获取这两个日期之间的间隔：

$date1 = '2018-07-13 13:00:00';
$date2 = '2018-07-14 16:01:00';

$interval = (new DateTime($date2))->diff(new DateTime($date1));
$totalHours = $interval->days * 24 + $interval->h;

echo sprintf("%02d", $totalHours) . ':' . sprintf("%02d", $interval->i);