我有一个应用程序,所有菜单项都来自下面的文件。我希望用户只能看到权限数组中的那些菜单?。下面是完整代码中的示例代码。
$db = mysqli_connect('localhost', 'cy57447_forms', '123456789', 'cy57447_forms');
if(isset($_POST['register'])) {
$email = mysql_real_escape_string($_POST['email']);
$tg_username = mysql_real_escape_string($_POST['tg_username']);
$bitcointalk_username = mysql_real_escape_string($_POST['bitcointalk_username']);
$bitcointalk_profile_link = mysql_real_escape_string($_POST['bitcointalk_profile_link']);
$twitter_account_url = mysql_real_escape_string($_POST['twitter_account_url']);
$number_of_followers = mysql_real_escape_string($_POST['number_of_followers']);
$twitter_audit_link = mysql_real_escape_string($_POST['twitter_audit_link']);
$ethereum_wallet = mysql_real_escape_string($_POST['ethereum_wallet']);
$tokens = '';
}
$sql = "INSERT INTO twitter_form (`tg_username`, `bitcointalk_username`, `bitcointalk_profile_link`, `twitter_account_url`, `number_of_followers`, `twitter_audit_link`, `ethereum_wallet`, `email`, `tokens`) VALUES ('$tg_username', '$bitcointalk_username', '$bitcointalk_profile_link', '$twitter_account_url', '$number_of_followers', '$twitter_audit_link', '$ethereum_wallet','$email', '');";
$result = mysqli_query($db, $sql);
答案 0 :(得分:2)
如果我没看错,您希望它创建一个用户可以看到的菜单。因此,在此示例中,用户将仅看到两个名为“添加角色”和“编辑角色”的条目,对吧?
创建一个Menù类,如下所示:
export class MenuEntities {
public state: string;
public name: string;
public target: boolean;
}
创建一个MenuEntities
数组来解析Json。我假设配置在以下代码行中:
children: [
{
state: 'add-roles',
name: 'Add Roles',
// target: true
},
{
state: 'edit-roles',
name: 'Edit Roles',
// target: true
}
]
创建数组并映射json res:
public menuEntities: MenuEntities[] = [];
// I let you do the logic to parse the json to this array.
一旦有了它,就可以开始了。只需将.html
文件循环到该数组中,便会得到一个菜单:
<ul *ngFor="let entity of menuEntities">
<li>States : {{entity.states}}</li>
<li>Name : {{entity.name}} </li>
</ul>
注意:如果您发布更多代码,我可以编辑此答案,但是这种逻辑很好用