Question

我要根据菜单项显示或隐藏插入符号图标。如果显示的菜单项显示插入符号图标，则将其隐藏。我正在使用bootstrap4，在我的情况下，下拉菜单项将动态生成。

.dropdown-toggle::after {
    display:none;!important
}

上面的代码删除了插入符号，但是如何根据是否存在下拉菜单显示/隐藏它呢？

.dropdown-toggle::after {
    display:none !important;
}

<meta name="viewport" content="width=device-width, initial-scale=1">
  <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.1.0/css/bootstrap.min.css">
  <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
  <script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.0/umd/popper.min.js"></script>
  <script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.1.0/js/bootstrap.min.js"></script>


<div class="dropdown">
    <button type="button" class="btn btn-primary dropdown-toggle" data-toggle="dropdown">
      Dropdown button
    </button>
    <div class="dropdown-menu">
      <a class="dropdown-item" href="#">Link 1</a>
      <a class="dropdown-item" href="#">Link 2</a>
      <a class="dropdown-item" href="#">Link 3</a>
    </div>
  </div>

Answer 1

如果.hide()中没有项目，请使用$('.dropdown-menu .dropdown-item').length==0

$( document ).ready(function() {
  if($('.dropdown-menu .dropdown-item').length==0 )
  {
   $('.fas.fa-shopping-cart').hide();
  }
});

<meta name="viewport" content="width=device-width, initial-scale=1">
  <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.1.0/css/bootstrap.min.css">
  <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
  <script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.0/umd/popper.min.js"></script>
  <script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.1.0/js/bootstrap.min.js"></script>
<link rel="stylesheet" href="https://use.fontawesome.com/releases/v5.1.0/css/all.css" integrity="sha384-lKuwvrZot6UHsBSfcMvOkWwlCMgc0TaWr+30HWe3a4ltaBwTZhyTEggF5tJv8tbt" crossorigin="anonymous">



<div class="dropdown">
    <button type="button" class="btn dropdown-toggle" data-toggle="dropdown">list<i class="fas fa-shopping-cart"></i>
 
    </button>
    <div class="dropdown-menu">
      <a class="dropdown-item" href="#">Link 1</a>
      <a class="dropdown-item" href="#">Link 2</a>
      <a class="dropdown-item" href="#">Link 3</a>
    </div>
</div>

仅CSS使用only-child:

.dropdown button:only-child .fas.fa-shopping-cart{
display:none;
}

    <meta name="viewport" content="width=device-width, initial-scale=1">
      <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.1.0/css/bootstrap.min.css">
      <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
      <script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.0/umd/popper.min.js"></script>
      <script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.1.0/js/bootstrap.min.js"></script>
    <link rel="stylesheet" href="https://use.fontawesome.com/releases/v5.1.0/css/all.css" integrity="sha384-lKuwvrZot6UHsBSfcMvOkWwlCMgc0TaWr+30HWe3a4ltaBwTZhyTEggF5tJv8tbt" crossorigin="anonymous">



    <div class="dropdown">
        <button type="button" class="btn dropdown-toggle" data-toggle="dropdown">list<i class="fas fa-shopping-cart"></i>
     
        </button>
    </div>

Answer 2

制作一个说.hidden的类，并为其添加display none属性。

.hidden {
display:none !important
}

并在您的JS中执行以下操作：

    $(document).ready(function(){


var hasElement = $(".dropdown-menu" ).has("a");

   hasElement.length == 0 ? $(".dropdown-toggle").addClass("hidden") : $(".dropdown-toggle").removeClass("hidden")
});

根据是否存在下拉菜单，在bootstrap4下拉菜单上显示或隐藏插入符号图标

2 个答案: