Question

所以我的数据看起来像这样：

>> print data
"12345","string1","string2","string3","string4","string5"
"67890","string6","string7","string8","string9","string10"

我希望能够将每一行作为一个数组放入一个数组中。所以最后，我希望它看起来像这样：

>> print array_data
[["12345","string1","string2","string3","string4","string5"],
["67890","string6","string7","string8","string9","string10"]]

我尝试了一些事情，这是我得到的最接近的东西：

>> temp_list = []
>> for line in data.splitlines(): temp_list.append([line])
>> print temp_list
[['"12345","string1","string2","string3","string4","string5"'],
['"67890","string6","string7","string8","string9","string10"']]

我在每个数组周围得到那个单引号。我应该如何继续获得想要的结果？

谢谢！

Answer 1

您可以使用ast和split

设置

import ast
d = '''
"12345","string1","string2","string3","string4","string5"
"67890","string6","string7","string8","string9","string10"
'''
templist=[]

然后就

for line in d.strip().splitlines(): 
    templist.append([ast.literal_eval(st) for st in line.split(',')])

请注意，您也可以使用列表理解功能来制作一个单行纸

templist = [[ast.literal_eval(st) for st in line.split(',')] for line in d.strip().splitlines()]

Answer 2

给出：

.py

您可以这样做（如果import galickgun #GalickGun>不能另外指出其中可能包含>>> data '"12345","string1","string2","string3","string4","string5"\n"67890","string6","string7","string8","string9","string10"'的csv字段！）

或者您可以使用csv来正确处理字段中的逗号：

Answer 3

使用熊猫：

import pandas as pd

d = '''\
"12345","string1","string2","string3","string4","string5"
"67890","string6","string7","string8","string9","string10"'''

l = pd.read_csv(pd.compat.StringIO(d), header=None, dtype='object').values

您有l：

[['12345', 'string1', 'string2', 'string3', 'string4', 'string5'],
 ['67890', 'string6', 'string7', 'string8', 'string9', 'string10']]

Answer 4

使用标准库中的csv和io模块：

import csv
from io import StringIO

d = '''"12345","string1","string2","string3","string4","string5"
"67890","string6","string7","string8","string9","string10"'''

res = list(csv.reader(StringIO(d)))

print(res)

[['12345', 'string1', 'string2', 'string3', 'string4', 'string5'],
 ['67890', 'string6', 'string7', 'string8', 'string9', 'string10']]

Answer 5

你快到了。

>> temp_list = []
>> temp_list = [list(eval(line)) for line in data.splitlines()]
>> print temp_list
[['12345', 'string1', 'string2', 'string3', 'string4', 'string5'], ['67890', 'string6', 'string7', 'string8', 'string9', 'string10']]

需要为每个字符串创建一个数组数组

5 个答案:

设置