Question

我正在尝试转换json中的响应

response = requests.get('http://solr.library.ucla.edu/solr/sheetmusic/select/?q=%5C*%20AND%20(url_keyword:http*)&version=2.2&start=0&rows=100&indent=on&facet=true&facet.field=r_date_facetRange&wt=json&json.wrf=jsonp1530647389471')
response = json.loads(response.content.decode('utf-8'))

但是我找回了这个错误

~/.virtualenvs/pistache/lib/python3.6/site-packages/requests/models.py in json(self, **kwargs)
        890                     # used.
        891                     pass
    --> 892         return complexjson.loads(self.text, **kwargs)
        893 
        894     @property

    /usr/lib/python3.6/json/__init__.py in loads(s, encoding, cls, object_hook, parse_float, parse_int, parse_constant, object_pairs_hook, **kw)
        352             parse_int is None and parse_float is None and
        353             parse_constant is None and object_pairs_hook is None and not kw):
    --> 354         return _default_decoder.decode(s)
        355     if cls is None:
        356         cls = JSONDecoder

    /usr/lib/python3.6/json/decoder.py in decode(self, s, _w)
        337 
        338         """
    --> 339         obj, end = self.raw_decode(s, idx=_w(s, 0).end())
        340         end = _w(s, end).end()
        341         if end != len(s):

    /usr/lib/python3.6/json/decoder.py in raw_decode(self, s, idx)
        355             obj, end = self.scan_once(s, idx)
        356         except StopIteration as err:
    --> 357             raise JSONDecodeError("Expecting value", s, err.value) from None
        358         return obj, end

    JSONDecodeError: Expecting value: line 1 column 1 (char 0)

Answer 1

此URL返回的不是JSON，而是JSONP。为了解析响应，您可以从url中删除最后一个参数（json.wrf=jsonp1530647389471）-然后响应将变为JSON，并且您可以使用json.loads进行解析。

response = requests.get('http://solr.library.ucla.edu/solr/sheetmusic/select/?q=%5C*%20AND%20(url_keyword:http*)&version=2.2&start=0&rows=100&indent=on&facet=true&facet.field=r_date_facetRange&wt=json')
print json.loads(response.content.decode('utf-8'))
# {u'facet_counts': {u'facet_ranges': {}...

或者，使其更简单：

response = requests.get('http://solr.library.ucla.edu/solr/sheetmusic/select/?q=%5C*%20AND%20(url_keyword:http*)&version=2.2&start=0&rows=100&indent=on&facet=true&facet.field=r_date_facetRange&wt=json').json()

Answer 2

如果必须使用相同的URL而不对其进行修改，则可以使用re模块来提取请求的响应内容中的JSON，如下例所示：

import re, json, requests

url = 'http://solr.library.ucla.edu/solr/sheetmusic/select/?q=%5C*%20AND%20(url_keyword:http*)&version=2.2&start=0&rows=100&indent=on&facet=true&facet.field=r_date_facetRange&wt=json&json.wrf=jsonp1530647389471'

resp = requests.get(url)
resp_parsed = re.sub(r'^jsonp\d+\(|\)\s+$', '', resp.text)
data = json.loads(resp_parsed)
print(data)

否则，另一个答案是正确的，并且使用起来更简单。

Answer 3

我收到解码错误，因为我在循环中读取数据并且连接超时或在几次“获取”后结束我尝试休眠几毫秒以克服此错误

    url = "https://api.coindcx.com/exchange/ticker"    
    while(True):
        t.sleep(0.5)
        resp = requests.get(url) 
        resp_parsed = re.sub(r'^jsonp\d+(|)\s+$', '', resp.text)    
        data = json.loads(resp_parsed)
        print(pd.DataFrame(data).query("market=='LINKINR'")['last_price'].values[0])

requests.json和json.loads（）JSONDecodeError：预期值：第1行第1列（字符0）

3 个答案: