Question

我正在尝试上传文件，然后将文件名插入数据库。

以下是我的代码：

<?php
//connecting to database
session_start();
include('/applications/MAMP/htdocs/connect.php');
$u = $_SESSION['username'];


if (!empty($_FILES)) {
$file = $_FILES['Filedata'];

    $tempFile = $_FILES['Filedata']['tmp_name'];
    $targetPath = $_SERVER['DOCUMENT_ROOT'] . $_REQUEST['folder'] . '/';
    $targetFile =  str_replace('//','/',$targetPath) . $_FILES['Filedata']['name'];

    // $fileTypes  = str_replace('*.','',$_REQUEST['fileext']);
    // $fileTypes  = str_replace(';','|',$fileTypes);
    // $typesArray = split('\|',$fileTypes);
    // $fileParts  = pathinfo($_FILES['Filedata']['name']);

    // if (in_array($fileParts['extension'],$typesArray)) {
        // Uncomment the following line if you want to make the directory if it doesn't exist
        // mkdir(str_replace('//','/',$targetPath), 0755, true);
        $n = $file['name'];
        move_uploaded_file($tempFile,$targetFile);
        echo str_replace($_SERVER['DOCUMENT_ROOT'],'',$targetFile);
        mysqli_select_db($connect,"people");
$i = "update users set filelocation = '$n' where sessionusername = '$u'";
$q = mysqli_query($connect,$i);
    // } else {
    //  echo 'Invalid file type.';
    // }
}


?>

文件正在成功上传，但该名称未在数据库中更新。

请帮帮我。

Answer 1

$n = $file['name'];将返回任何内容，因为$ file未在任何地方声明。您可能想要使用：

$n = $_FILES['Filedata']['name'];

或其他任何声明你真的想要放入数据库的内容; - ）

Answer 2

你有$n = $file['name'];

应为$n = $targetFile

但首先 - 清理你的代码;）

我为你清理了它。检查这是否有效。

<?php
session_start();
include('/applications/MAMP/htdocs/connect.php');
mysqli_select_db("people");

if (!isset($_REQUEST['folder'])) $_REQUEST['folder'] = "";

if (!empty($_FILES)) {
    $tempFile = $_FILES['Filedata']['tmp_name'];
    $targetPath = $_SERVER['DOCUMENT_ROOT'] . $_REQUEST['folder'] . '/';
    $targetFile =  str_replace('//','/',$targetPath) . $_FILES['Filedata']['name'];

    move_uploaded_file($tempFile,$targetFile);
    $i = "UPDATE users SET filelocation = '$targetFile' WHERE sessionusername = '{$_SESSION['username']}'";
    $q = mysqli_query($i);

    //debug
    echo "$targetFile<br/>
        $tempFile<br/>
        $i<br/>";
    echo mysqli_error();
}
else {
    echo "No file";
}
?>

上载文件后更新数据库的问题

2 个答案: