我有一个ASP.NET Core Service,它可以生成JSON和XML响应。但是,我只想限制一个动作接受的媒体类型,因此Swagger只能将application / json列为有效的响应内容类型。如何在ASP.Net Core中实现这一目标?
请考虑我使用的是ASP.Net Core(ASP.NET MVC 6),而不是ASP.NET WebAPI。
更新
好的,所以我将答案添加为同一问题的一部分。感谢@Helen,我能够在ASP.Net Core(ASP.Net MVC 6)中添加所需的类来实现此目的。答案基于this answer,但已修改为使用ASP.NET Core类。
第1步。 创建自定义操作过滤器属性,以便管道对禁止的内容类型做出反应:
/// <summary>
/// SwaggerResponseContentTypeAttribute
/// </summary>
[AttributeUsage(AttributeTargets.Method)]
public sealed class SwaggerResponseContentTypeAttribute : ActionFilterAttribute
{
/// <summary>
/// SwaggerResponseContentTypeAttribute
/// </summary>
/// <param name="responseType"></param>
public SwaggerResponseContentTypeAttribute(string responseType)
{
ResponseType = responseType;
}
/// <summary>
/// Response Content Type
/// </summary>
public string ResponseType { get; private set; }
/// <summary>
/// Remove all other Response Content Types
/// </summary>
public bool Exclusive { get; set; }
public override void OnActionExecuting(ActionExecutingContext context)
{
var accept = context.HttpContext.Request.Headers["accept"];
var accepted = accept.ToString().ToLower().Contains(ResponseType.ToLower());
if (!accepted)
context.Result = new StatusCodeResult((int)HttpStatusCode.NotAcceptable);
}
}
第2步 。创建一个Swagger操作过滤器,以便UI可以反映限制
public class ResponseContentTypeOperationFilter : IOperationFilter
{
public void Apply(Swashbuckle.AspNetCore.Swagger.Operation operation, OperationFilterContext context)
{
var requestAttributes = context.ControllerActionDescriptor.GetControllerAndActionAttributes(true).Where(c=>c.GetType().IsAssignableFrom(typeof(SwaggerResponseContentTypeAttribute))).Select(c=> c as SwaggerResponseContentTypeAttribute).FirstOrDefault();
if (requestAttributes != null)
{
if (requestAttributes.Exclusive)
operation.Produces.Clear();
operation.Produces.Add(requestAttributes.ResponseType);
}
}
}
第3步。 在Startup.cs中的ConfigureServices方法内配置Swagger UI服务,以便它可以使用新创建的Operation Filter。
// This method gets called by the runtime. Use this method to add services to the container.
public void ConfigureServices(IServiceCollection services)
{
services.AddMvc();
services.Configure<MvcOptions>(options =>
{
options.OutputFormatters.Add(new XmlDataContractSerializerOutputFormatter());
});
// Register the Swagger generator, defining 1 or more Swagger documents
services.AddSwaggerGen(c =>
{
c.SwaggerDoc("v1", new Info { Title = "My API", Version = "v1" });
c.OperationFilter<ResponseContentTypeOperationFilter>();
});
}
第4步 。注释动作
// GET api/values
[HttpGet]
[WebService.Utils.SwaggerResponseContentType(responseType: "application/json", Exclusive = true)]
public IEnumerable<string> Get()
{
return new string[] { "value1", "value2" };
}
答案 0 :(得分:3)
您可以使用注释消费和生产。这些也由Swashbuckle领取。 像这样:
[HttpGet]
[Consumes("application/xml")]
[Produces("application/xml")]
public IEnumerable<string> Get()
{
return new string[] { "value1", "value2" };
}