通过组合列表和字符串创建字符串列表

Question

我正在尝试创建一个包含两个列表和一些字符串的列表：

string = "test"
list1 = ["1","2","3"]
list2 = ["a","b","c"]

result = ["test.1.a","test.2.b","test.3.b"]

我尝试弄乱.join和zip函数，但无济于事。

Answer 1

我相信，可以使用zip和Dockerfile来实现以下pythonic方式：

list comprehension

Answer 2

这有效：

['.'.join((string,)+i) for i in zip(list1, list2)]

输出：

['test.1.a', 'test.2.b', 'test.3.c']

Answer 3

string = "test"
list1 = ["1","2","3"]
list2 = ["a","b","c"]

lst = ['{}.{}.{}'.format(string, list1[x], list2[x]) for x in range(len(list1))]

print(lst)

输出

['test.1.a', 'test.2.b', 'test.3.c']

Answer 4

只需使用concatenation技巧：

string1 = "test"
list1 = ["1","2","3"]
list2 = ["a","b","c"]

result = [(string1+"."+list1[i]+"."+list2[i]) for i in range(len(list1))]
print(result)

输出：

['test.1.a', 'test.2.b', 'test.3.c']

Answer 5

列表理解：

string = "test"
list(map(lambda x,y: string+"."+x+"."+y, list1,list2))

输出：

['test.1.a', 'test.2.b', 'test.3.c']