首先我从BIRTHDAYS
得到了工人的名字,然后又想从e-mail address
得到了USERS
。从Table1
取得工人的名字是没有问题的,但是当我尝试时要获取数据库的电子邮件地址,数据库将返回NULL
。我的数据库是mssql。
<?php
include_once("connect.php");
$today = '05.07';
$today1 = $today . "%";
$sql = "SELECT NAME FROM BIRTHDAYS WHERE BIRTH LIKE '$today1' ";
$stmt = sqlsrv_query($conn,$sql);
if($stmt == false){
echo "failed";
}else{
$dizi = array();
while($rows = sqlsrv_fetch_array($stmt,SQLSRV_FETCH_ASSOC))
{
$dizi[] = array('NAME' =>$rows['NAME']);
$newarray = json_encode($dizi,JSON_UNESCAPED_UNICODE);
}
}
foreach(json_decode($newarray) as $nameObj)
{
$nameArr = (array) $nameObj;
$names = reset($nameArr);
mb_convert_case($names, MB_CASE_UPPER, 'UTF-8');
echo $sql2 = "SELECT EMAIL FROM USERS WHERE NAME = '$names' ";
echo "<br>";
$stmt2 = sqlsrv_query($conn,$sql2);
if($stmt2 == false)
{
echo "failed";
}
else
{
$dizi2 = array();
while($rows1 = sqlsrv_fetch_array($stmt2,SQLSRV_FETCH_ASSOC))
{
$dizi1[] = array('EMAIL' =>$rows['EMAIL']);
echo $newarray1 = json_encode($dizi1,JSON_UNESCAPED_UNICODE);
}
}
}
?>
答案 0 :(得分:1)
while($rows1 = sqlsrv_fetch_array($stmt2,SQLSRV_FETCH_ASSOC))
{
$dizi1[] = array('EMAIL' =>$rows['EMAIL']);
echo $newarray1 = json_encode($dizi1,JSON_UNESCAPED_UNICODE);
}
您放入$ rows1并从$ rows中取出NULL是正确答案:)
使用$rows1['EMAIL']
,它将起作用
以及为什么foreach =?
您可以将语句放入while循环中,如下所示:
while ($rows = sqlsrv_fetch_array($stmt, SQLSRV_FETCH_ASSOC)) {
$names = $rows['NAME'];
$sql2 = "SELECT EMAIL FROM USERS WHERE NAME = '$names' ";
echo "<br>";
$stmt2 = sqlsrv_query($conn, $sql2);
if ($stmt2 == false) {
echo "failed";
} else {
$dizi2 = array();
while ($rows1 = sqlsrv_fetch_array($stmt2, SQLSRV_FETCH_ASSOC)) {
$dizi1[] = array('EMAIL' => $rows1['EMAIL']);
echo $newarray1 = json_encode($dizi1, JSON_UNESCAPED_UNICODE);
}
}
}