Question

我找不到一种方法来划分我的2个查询的结果。

它们看起来像这样：

SELECT periode, cee_ref_no, SUM(somme) AS total FROM V_STAT_NAMUR 
WHERE code_ref_no IN (1, 2, 3, 4, 5, 6, 193, 215, 237, 259, 281)
AND periode BETWEEN '201401' AND '201412'
AND cee_ref_no = '961'
GROUP BY periode, cee_ref_no
ORDER BY periode;

AND

SELECT periode, cee_ref_no, SUM(somme) AS total FROM V_STAT_NAMUR
WHERE code_ref_no IN (7, 8, 9, 10, 205, 227, 249, 271, 293)
AND periode BETWEEN '201401' AND '201412'
AND cee_ref_no = '961'
GROUP BY periode, cee_ref_no
ORDER BY periode;

它们看起来很相似，并且都返回如下内容：

 DATE  | CEE_REF_NO | TOTAL
201401 |   961      | 10713
201402 |   961      | 9593
...    |   961      | ...
201412 |   961      | 10426

如何合并这些以获得类似的内容：

 DATE  | CEE_REF_NO | TOTAL
201401 |   961      | Total Q1/ Total Q2
201402 |   961      | Total Q1/ Total Q2
...    |   961      | ...
201412 |   961      | Total Q1/ Total Q2

我尝试过的所有结果都只返回一行，或者返回12行，结果相同。

非常感谢！

Answer 1

使用条件聚合：

SELECT periode, cee_ref_no,
       SUM(CASE WHEN code_ref_no IN (1, 2, 3, 4, 5, 6, 193, 215, 237, 259, 281) THEN somme ELSE 0 END) AS total_1,
       SUM(CASE WHEN code_ref_no IN (7, 8, 9, 10, 205, 227, 249, 271, 293) THEN somme ELSE 0 END) AS total_2,
       (SUM(CASE WHEN code_ref_no IN (1, 2, 3, 4, 5, 6, 193, 215, 237, 259, 281) THEN somme ELSE 0 END) /
        SUM(CASE WHEN code_ref_no IN (7, 8, 9, 10, 205, 227, 249, 271, 293) THEN sommeEND)
       ) AS ratio
FROM V_STAT_NAMUR 
WHERE  AND
      periode BETWEEN '201401' AND '201412'
GROUP BY periode, cee_ref_no
ORDER BY periode;

Answer 2

您可以尝试以下操作：

select q1.periode, q1.cee_ref_no, q1.total as Total1, q2.total as Total2, q1.total/q2.total as Division
from (
    SELECT periode, cee_ref_no, SUM(somme) AS total FROM V_STAT_NAMUR 
    WHERE code_ref_no IN (1, 2, 3, 4, 5, 6, 193, 215, 237, 259, 281)
    AND periode BETWEEN '201401' AND '201412'
    AND cee_ref_no = '961'
    GROUP BY periode, cee_ref_no
  ) q1
  join (
    SELECT periode, cee_ref_no, SUM(somme) AS total FROM V_STAT_NAMUR
    WHERE code_ref_no IN (7, 8, 9, 10, 205, 227, 249, 271, 293)
    AND periode BETWEEN '201401' AND '201412'
    AND cee_ref_no = '961'
    GROUP BY periode, cee_ref_no
  ) q2
  on q1.Periode=q2.Periode
 and q1.cee_ref_no=q2.cee_ref_no

基本上，您只需使用查询创建2个子选择，然后按句点和cee_ref_no将它们连接起来（如果要包括1个以上cee_ref_no，则在示例中只有一个）。然后您就可以将合计除以q1和q2。

请注意联接，我不知道您的数据是否在两个查询中都包含所有月份的信息。

PS：查询未经测试，直接在编辑器上编写。

Answer 3

尝试一下

    Select periode, cee_ref_no, total1/total2 as Total
    From (
    SELECT periode, cee_ref_no, 
    sum(Case when code_ref_no in (1, 2, 3, 4, 5, 6, 193, 215, 237, 259, 281) Then somme else 0 end) as total1,
    sum(Case when code_ref_no in (7, 8, 9, 10, 205, 227, 249, 271, 293) Then somme else 0 end) as total2
    From my_table
WHERE code_ref_no IN (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 193, 205, 215, 227, 237, 249, 259, 271, 281, 293)
    AND periode BETWEEN '201401' AND '201412'
    AND cee_ref_no = '961'
    GROUP BY periode, cee_ref_no
    )
    ORDER BY periode;

2个查询元素wis的除法结果

3 个答案: