Question

我正在使用CI 3.1.9，并在下面的HTML表单中，使用如下键和值从PHP创建动态输入：

<form action="<?= base_url();?>/process" method="post">
<?php
   foreach ($invoices as $invoice) {
   // $invoice has values like 124-55441
?>
   <input type="text" name="amounts[<?= $invoice; ?>]">
<?php } ?>
   <input type="submit", value="submit">
</form>

现在在config文件夹中，我放置了一个带有验证规则数组的form_validation.php文件，如下所示：

<?php
defined('BASEPATH') OR exit('No direct script access allowed');
/* Custom Validation Rules */
$config = array(
    'invoices' => array(
        array(
            'field' => 'amounts[]',
            'rules' => 'trim|callback_checkAmountsToPay'
        )
    );
?>

在我的控制器Process.php中，我放置了以下代码：

<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class Process extends CI_Controller {
   public function index(){
    if ($this->input->method(TRUE) === "POST") {
            if ($this->form_validation->run("invoices") == FALSE) {
                echo "Validation Failed";
            } else {
                $amounts = $this->input->post("amounts");
                var_dump($amounts);
            }
        } else {
            $this->load->view('invoices');
            //Loading the form to view
        }
   }
   //Custom validation form 
   public function checkAmountsToPay($arrAmounts) {
        var_dump($arrAmounts);//Shows empty value
        $this->input->post("amounts"); //Shows all array sent by the form.
        die();
   }
}
?>

checkAmountsToPay定制验证方法始终显示由表单发送的输入数组“ amounts []”的空值，但是如果我输入$ this-> input-> post（“ amounts”）;它显示了整个数组，所以为什么post参数没有发送到自定义验证功能？

谢谢。

Answer 1

由于arrays表单验证库的限制，没有正确的方法在回调或验证规则中使用Codeigniter's，因此您必须使用字符串。

尝试一下：

if ($this->input->method(TRUE) === 'POST') {
    $amounts = json_encode($this->input->post('amounts'));
    $this->form_validation->set_rules('amounts', 'Amounts', 'callback_checkAmountsToPay[' . $amounts . ']');
    if ($this->form_validation->run('invoices') == FALSE) {
        echo 'Validation Failed';
    } else {
        $amounts = $this->input->post('amounts');
        var_dump($amounts);
    }
} else {
    $this->load->view('welcome_message');
    //Loading the form to view
}

像这样得到：

public function checkAmountsToPay($value, $amounts) {  
    // $value returns first value of $_POST['amounts'][0]
    $amounts = json_decode($amounts);
    print_r($amounts);
}

或者只是用作回调函数中的代码

$this->input->post('amounts');

Codeigniter 3.1.9传递和验证数组输入无效

1 个答案: