Question

我正在使用CodeIgniter，我的问题是关于MySQL查询的。我有两个表，分别是成员和关系。

成员表

我正在做的是，我正在根据member_type在成员表中添加所有用户。如果member_type为1，则为主要成员；如果为2，则为次要成员

关系表

在关系表中，我正在定义用户的关系。例如primary_member_id为1，则次要成员为3和6，次要成员详细信息在成员表中可用。

现在，我需要查询以显示列表中的所有主要成员，并与它们的次要成员名称和其他详细信息有关。

我正在使用带有子行的数据表。这样我就可以在列表中显示主要名称，然后单击加号以显示次要成员。

我尝试了以下联接代码。

SELECT * FROM `member` LEFT JOIN relation on member.id=relation.primary_member_id WHERE member.member_type=1

下面的

是上面查询的输出。在这种情况下，我要获得两次主要成员名称以及如何显示次要成员名称

我需要一个输出

数据表

     function format ( d ) {
    return '<table cellpadding="5" cellspacing="0" border="0" style="padding-left:50px;">'+
        '<tr>'+
            '<td>Full name:</td>'+
            '<td>'+d.name+'</td>'+
        '</tr>'+
        '<tr>'+
            '<td>Mobile number:</td>'+
            '<td>'+d.phone+'</td>'+
        '</tr>'+
        '<tr>'      
    '</table>';
}
$(document).ready(function() {
            var oTable =$('#all_list').DataTable( {
                "processing": true,
                // "serverSide": true,
                "pageLength": 10,
                "ajax": {
                    "url": baseUrl+ "/index.php/Search/Listdetails_ajax",
                    "type": "POST"
                },
                "columns": [
                   {
                "className":      'details-control',
                "orderable":      false,
                "data":           null,
                "defaultContent": ''
                    },
                { "data": "profile_pic","className":"img_list_pic",
                "render": function (data, type, full, meta) {
                return '<img src='+baseUrl+'/uploads/images/'+data+' class="search_pic">';
                }
                 },
                { "data": "name" },
                { "data": "phone" }
            ],
               "order": [[1, 'asc']],


            } );
    $('#all_list tbody').on('click', 'td.details-control', function () {
        var tr = $(this).closest('tr');
        var row = oTable.row( tr );

        if ( row.child.isShown() ) {
            // This row is already open - close it
            row.child.hide();
            tr.removeClass('shown');
        }
        else {
            // Open this row
            row.child( format(row.data()) ).show();
            tr.addClass('shown');
        }
    } );

} );

ajax

public function Listdetails_ajax(){  
    $draw = intval($this->input->get("draw"));
    $start = intval($this->input->get("start"));
    $length = intval($this->input->get("length"));
    $books = $this->Search_model->getTotalList_of_primary();
    $books_of_secondary = $this->Search_model->getTotalList_of_secondary();

    $data['draw'] = 1;
    $data['recordsTotal'] = count($books);
    $data['recordsFiltered'] = count($books);
    foreach ($books as $key => $row) 
    {
        $arr_result = array(
                   "profile_pic" => $row->profile_pic,
                   "name" => $row->first_name.' ' .$row->last_name,
                    "phone" => $row->phone
        );
        $data['data'][] = $arr_result;
      }
      //print_r($arr_result);
    echo json_encode($data);
    exit;
}

/ 模型 /

public function getTotalList_of_primary(){
      $this->db->select('*');
      $this->db->from('member');
      $this->db->where('member_type',1);
      $query = $this->db->get();
      $res   = $query->result();        
     return $res;
}

public function getTotalList_of_secondary(){
    /*what query I have to use here*/
}

Answer 1

遵循details row中所使用的详细信息弹出框的想法，控制器将如下所示：

public function Listdetails_ajax(){  
   $draw = intval($this->input->get("draw"));
    $start = intval($this->input->get("start"));
    $length = intval($this->input->get("length"));
    $books = $this->Search_model->getTotalList_of_primary();

    $data['draw'] = 1;
    $data['recordsTotal'] = count($books);
    $data['recordsFiltered'] = count($books);
    foreach ($books as $key => $row) 
    {
        //print_r($row->customer_id);
        $arr_result = array(
                    "member_id" => base64_encode($this->encryption->encrypt($row->member_id)),
                    "profile_pic" => $row->profile_pic,
                    "name" => $row->first_name.' ' .$row->last_name,
                    "phone" => $row->phone,
                    "chss_no" => $row->chss_no,
                    "emp_id" => $row->emp_id,
                    "address" => $row->address
                    // "member_type" => $row->member_type
        );

         $array_secondary = array();
         $books_of_secondary = $this->Search_model->getTotalList_of_secondary($row->customer_id);
         foreach ($books_of_secondary as $key => $row) 
            {
                //print_r($row->customer_id);
                $arr_result2 = array(
                            "s_member_id" => base64_encode($this->encryption->encrypt($row->member_id)),
                            "s_profile_pic" => $row->profile_pic,
                            "s_name" => $row->first_name.' ' .$row->last_name,
                            "s_phone" => $row->phone,
                            "s_chss_no" => $row->chss_no,
                            "s_emp_id" => $row->emp_id,
                            "s_address" => $row->address
                );


                $array_secondary[] = $arr_result2;
            }
         $arr_result['secondary'] =  $array_secondary;  
         $data['data'][] = $arr_result;
      }
    echo json_encode($data);
    exit;
}

然后在format函数中，您将访问secondary字段以获取第二数组。也许像这样：

function format(d) {
    // d is the original data object for the row var val;
    if(d.secondary.length == 0) {
        return "There are no secondary members";
    }

    var display = '<table cellpadding="5" cellspacing="0" border="0" style="padding-left:50px;">'; 
    for (val of d.secondary) { 
        display += '<tr>' + '<td>Full name:</td>' + '<td>' + val.s_name + '</td>' + '</tr>' + '<tr>' + '<td>Mobile number:</td>' + '<td>' + val.s_phone + '</td>' + '</tr>';
    }
    display += '</table>';
    return display;
}

Answer 2

您可以使用两个查询来实现。

首先获取所有主要成员以显示主要成员列表。

select * from Member m where m.member_type = 1;

第二个获取该主要成员ID的所有次要成员。

select * from Member m
join Relation r where m.member_id = r.secondary_member_id and 
r.primary_member_id = :primaryMemberId;

如何显示主要成员列表以及次要成员详细信息

2 个答案: