Question

我有一组结果，例如发票。

他们想要一组结果，列出每个发票中的项目，但每个结果旁边都有一个行号。

我目前所拥有的（已修改为适合问题）；

SELECT
         [jvi].[name] AS [ScheduledCode],
         [jvi].[description] AS [Description],
         [clientReference] AS [TracksheetRef],
         (SELECT TOP 1 COUNT(*) FROM [table2items] [jvi1] WHERE [jvi1].[SheetId] = [jvs].[id]) AS [Line],
         (SELECT TOP 1 SUM(CAST(([jvi1].[Cost] * [jvi1].[qty]) AS MONEY)) FROM [table2items] [jvi1] WHERE [jvi1].[valuationSheetId] = [jvs].[id]) AS [UpliftedValue],

FROM
         [dbo].[table1invoice] [jvs]
INNER JOIN
         [dbo].[table2items] [jvi] ON [jvi].[SheetId] = [jvs].[id]



ScheduledCode     Description                   Ref    Lines    UpliftedValue
C142011         RepairMain/90-150mm/Unmade  0227-0318   1         303.68
C182912             Surfaced                4237-0518   1         211.58
C182912              Install                4626-0518   2         356.24
C182811      Investigation / Unmade         4626-0518   2         356.24
C182811            Poor Supply              3460-0118   2         356.24

如您所见，它计算每张纸有多少行，但我需要在每张纸旁边添加一个数字并向上计数，例如：

1    C182811     Investigation / Unmade         4626-0118   2         356.24
2    C182811               Poor Supply          3460-0118   2         356.24
1    C182912                Surfaced            4237-0518   1         211.58
2    C182912                 Install            4626-0518   2         356.24

Answer 1

只需使用：

row_number() over 
(partition by ScheduledCode order by ScheduledCode, UpliftedValue, Description) as rowNum

作为查询的最左列，如下所示：

SELECT row_number() over 
      (partition by q.ScheduledCode order by q.ScheduledCode, q.UpliftedValue,q.Description ) as rowNum,
       q.*
  FROM
(
SELECT
         [jvi].[name] AS [ScheduledCode],
         [jvi].[description] AS [Description],
         [clientReference] AS [TracksheetRef],
         (SELECT TOP 1 COUNT(*) FROM [table2items] [jvi1] WHERE [jvi1].[SheetId] = [jvs].[id]) AS [Line],
         (SELECT TOP 1 SUM(CAST(([jvi1].[Cost] * [jvi1].[qty]) AS MONEY)) FROM [table2items] [jvi1] WHERE [jvi1].[valuationSheetId] = [jvs].[id]) AS [UpliftedValue],

FROM
         [dbo].[table1invoice] [jvs]
INNER JOIN
         [dbo].[table2items] [jvi] ON [jvi].[SheetId] = [jvs].[id]
) q

SQL Fiddle Demo

如何对每个订单项进行计数

1 个答案: