我的postresql中有这些表:-
1.付款方式(编号,编号,金额)
2.发票(编号,编号,金额)
和用于将付款金额分配给发票的invoice_payment表
3.InvoicePayment(id,payment_id,invoice_id,金额)
可以将单笔付款分配给许多发票。
现在我需要付款明细,但我也要有发票。此付款分配的发票编号。我正在做这样的事情:-
SELECT
payments.number,
payments.amount,
(SELECT invoices.number from invoices INNER JOIN invoice_payments
ON invoices.id = invoice_payments.invoice_id
WHERE invoice_payments.payment_id = payments.id)
from payments
但是它给我的错误超过了子查询返回的一行。如何使每个付款行的发票号逗号分隔? 样本数据:-
Payment
id number amount
1 "Pay001" 100
2 "Pay002" 150
3 "Pay003" 150
Invoice
id number amount
1 "INV001" 100
2 "INV002" 200
3 "INV003" 100
InvoicePayment
id payment_id invoice_id amount
1 1 1 50
2 1 2 50
3 2 2 150
4 3 1 50
5 3 3 100
Result:-
payment_id payment_number amount invoices
1 "Pay001" 100 "INV001, INV002"
2 "Pay002" 150 "INV002"
3 "Pay003" 150 "INV001, INV002"
答案 0 :(得分:1)
您可以在postgres中使用string_agg
函数来连接行,并以选定的分隔符分隔。
SELECT
payments.number,
payments.amount,
(SELECT string_agg(invoices.number,',') from invoices INNER JOIN invoice_payments
ON invoices.id = invoice_payments.invoice_id
WHERE invoice_payments.payment_id = payments.id)
from payments
答案 1 :(得分:1)
尝试一下
SELECT
payments.number,
payments.amount,
inv_p.inv_no
from payments p inner join (Select invoice_payments.payment_id, string_agg(invoices.number,',') as inv_no
From invoices inner join invoice_payments on (invoices.id = invoice_payments.invoice_id)
Group by invoice_payments.payment_id) inv_p on (p.id = inv_p.payment_id)