Question

我对xmltable进行了查询：

WITH sample_data AS(

    SELECT 10001 ID, '"A","B","C"' str, '"val_a","val_b","val_e"' numf FROM dual UNION ALL
    SELECT 10002 ID, '"D","E","F"' str, '"val_c","val_a","val_z"' numf FROM dual UNION ALL
    SELECT 10003 ID, '"C","E","G"' str, '"val_q","val_f","val_p"' numf FROM dual
    )

    SELECT id,
           trim(n.getstringval()) str
    FROM sample_data,
         xmltable(str) n

结果我得到：

 --id--|--str---
 10001 |   A
 10001 |   B
 10001 |   C
 10002 |   D
 10002 |   E
 10002 |   F
 10003 |   C
 10003 |   E
 10003 |   G

现在我需要得到这个结果：

 --id--|--str--|--numf--
 10001 |   A   |  val_a
 10001 |   B   |  val_b
 10001 |   C   |  val_e
 10002 |   D   |  val_c
 10002 |   E   |  val_a
 10002 |   F   |  val_z
 10003 |   C   |  val_q
 10003 |   E   |  val_f
 10003 |   G   |  val_p

如何更新查询以获得此结果？

Answer 1

您可以使用：

WITH sample_data AS(
    SELECT 10001 ID, '"A","B","C"' str, '2,3,4' numf FROM dual UNION ALL
    SELECT 10002 ID, '"D","E","F"' str, '5,6,7' numf FROM dual UNION ALL
    SELECT 10003 ID, '"C","E","G"' str, '8,9,10'numf FROM dual
), cte2 AS (
SELECT id,
       trim(n.getstringval()) str,
       NULL AS numf,
       rownum AS r
FROM sample_data, xmltable(str) n
UNION ALL
SELECT id,
       NULL,
       trim(n.getstringval()) numf,
       rownum
FROM sample_data, xmltable(numf) n
)
SELECT MIN(ID) AS ID, MIN(str) AS str, MIN(numf) AS numf
FROM cte2
GROUP BY r
ORDER BY ID, str;

DBFiddle Demo

输出：

┌───────┬─────┬──────┐
│  ID   │ STR │ NUMF │
├───────┼─────┼──────┤
│ 10001 │ A   │    2 │
│ 10001 │ B   │    3 │
│ 10001 │ C   │    4 │
│ 10002 │ D   │    5 │
│ 10002 │ E   │    6 │
│ 10002 │ F   │    7 │
│ 10003 │ C   │    8 │
│ 10003 │ E   │    9 │
│ 10003 │ G   │   10 │
└───────┴─────┴──────┘

从xmltable oracle中选择几个字段

1 个答案: