嗨,我尝试创建一个将请求参数接受为LocalDateTime的控制器。
ex: /api/actions?page=0&size=10&from=2018-05-02T20:20:20&to=2018-06-02T20:20:20
在控制器中,如果我使用下面的代码,它将起作用:
@RequestParam(value = "from")
@DateTimeFormat(iso = DateTimeFormat.ISO.DATE_TIME)
LocalDateTime from,
@RequestParam(value = "to")
@DateTimeFormat(iso = DateTimeFormat.ISO.DATE_TIME)
LocalDateTime to
但是我想将@DateTimeFormat移到全局配置,然后选择ObjectMapper:
我在配置中创建一个bean:
@Bean
public ObjectMapper jacksonObjectMapper() {
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);
JavaTimeModule javaTimeModule = new JavaTimeModule();
javaTimeModule.addSerializer(
LocalDateTime.class,
new LocalDateTimeSerializer(DateTimeFormatter.ofPattern(dateTimeFormat)));
objectMapper.registerModule(javaTimeModule);
return objectMapper;
}
然后尝试
@Bean
public ObjectMapper objectMapper(Jackson2ObjectMapperBuilder builder) {
ObjectMapper objectMapper = builder.createXmlMapper(false).build();
objectMapper.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);
JavaTimeModule javaTimeModule = new JavaTimeModule();
javaTimeModule.addSerializer(
LocalDateTime.class,
new LocalDateTimeSerializer(DateTimeFormatter.ofPattern(dateTimeFormat)));
objectMapper.registerModule(javaTimeModule);
return objectMapper;
}
这是dateTimeFormat值:yyyy-MM-dd'T'HH:mm:ss.SS
以上两种方法都不起作用,它说:
org.springframework.web.method.annotation.MethodArgumentTypeMismatchException类:无法将类型“ java.lang.String”的值转换为所需类型“ java.time.LocalDateTime”;嵌套异常是org.springframework.core.convert.ConversionFailedException:无法从类型[java.lang.String]转换为类型[@ org.springframework.web.bind.annotation.RequestParam java.time.LocalDateTime]的值'2018 -05-02T20:20:20';嵌套异常为java.lang.IllegalArgumentException:解析尝试失败,无法获取值[2018-05-02T20:20:20]
我的杰克逊版本:
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
<version>2.8.8</version>
</dependency>
我想念什么吗? 谢谢您的宝贵时间。
答案 0 :(得分:0)
org.springframework.web.method.annotation.MethodArgumentTypeMismatchException类:无法将类型“ java.lang.String”的值转换为所需类型“ java.time.LocalDateTime”;嵌套的异常是org.springframework.core.convert.ConversionFailedException
我认为在这里您需要使用 JsonSerializer 和 JsonDeserializer 。
因此,当请求发出时,您使用 JsonDeserializer ,它将把您的String格式的日期转换为所需的Date格式。这是代码,
@Component
public class DateDeSerializer extends JsonDeserializer<Date> {
public final SimpleDateFormat formatter = new SimpleDateFormat("date format");
@Override
public Date deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException {
if (jp.getCurrentToken().equals(JsonToken.VALUE_STRING)) {
try {
return formatter.parse(jp.getText());
} catch (ParseException e) {
// throw exception
}
}
return null;
}
@Override
public Class<Date> handledType() {
return Date.class;
}
}
要格式化响应,请使用 JsonSerializer 。这是示例代码,
@Component
public class DateSerializer extends JsonSerializer<Date> {
DateFormat formatter = new SimpleDateFormat("date format");
@Override
public void serialize(Date value, JsonGenerator gen, SerializerProvider serializers) throws IOException {
gen.writeObject(formatter.format(value));
}
@Override
public Class<Date> handledType() {
return Date.class;
}
}
答案 1 :(得分:0)
问题是我在requestParam传递LocalDateTime,但是我使用的ObjectMapper仅适用于请求的主体。
要解决我的问题,我创建了新组件LocalDateTimeConverter并删除了ObjectMapper的bean。
@Component
public class LocalDateTimeConverter implements Converter<String, LocalDateTime> {
private final DateTimeFormatter formatter;
@Autowired
public LocalDateTimeConverter(@Value("${dateTime.format}") String dateTimeFormat) {
this.formatter = DateTimeFormatter.ofPattern(dateTimeFormat);
}
@Override
public LocalDateTime convert(String source) {
if (source == null || source.isEmpty()) {
return null;
}
return LocalDateTime.parse(source, formatter);
}
}