Question

test_tweets = [
  "This president sucks!",
  "I hate this Blank House!",
  "I can't believe we're living with such a bad leadership. We were so foolish",
  "President Presidentname is a danger to society. I hate that he's so bad – it sucks."
  ]

banned_phrases = ["sucks", "bad", "hate", "foolish", "danger to society"]

写一个程序，从推文中过滤掉以下单词：“吸”，“坏”，“仇恨”，“愚蠢”和“危害社会”。替换每个否定词或在其上加上“已删除”一词。

不确定如何执行此操作。有人可以照亮吗？

new_array = test_tweets.join(" ").split(" ")
new_array.map { |word| word == banned_phrases.to_s ? "CENSORED" : word }.flatten!

Answer 1

您要将整个banned_phrases数组转换为字符串，这将返回类似的内容

"[\"sucks\", \"bad\", \"hate\", \"foolish\", \"danger to society\"]"

因此，任何推文中都没有一个词可以等于（或可能不会）。主要问题似乎在于比较。

您可以开始遍历每个tweet，将它们拆分，将每个单词放入其中，然后检查包含被禁止短语的数组是否包含该特定单词，如果是，则返回“ CENSORED”，否则返回该单词。然后，您可以使用空格将生成的数组中的每个单词连接起来：

test_tweets = [
  "This president sucks!",
  "I hate this Blank House!",
  "I can't believe we're living with such a bad leadership. We were so foolish",
  "President Presidentname is a danger to society. I hate that he's so bad – it sucks."
]

banned_phrases = ["sucks", "bad", "hate", "foolish", "danger to society"]

censored_tweets = test_tweets.flat_map do |tweet|
  tweet.split.map { |word| banned_phrases.include?(word) ? 'CENSORED' : word }.join(' ')
end
p censored_tweets
# ["This president sucks!", "I CENSORED this Blank House!", "I can't believe we're living with such a CENSORED leadership. We were so CENSORED", "President Presidentname is a danger to society. I CENSORED that he's so CENSORED – it sucks."]

test_tweets.flat_map do |tweet|
  re = Regexp.union(banned_phrases)
  tweet.split.map { |word| word.gsub(re, 'CENSORED') }.join(' ')
end
# ["This president CENSORED!", "I CENSORED this Blank House!", "I can't believe we're living with such a CENSORED leadership. We were so CENSORED", "President Presidentname is a danger to society. I CENSORED that he's so CENSORED – it CENSORED."]

Answer 2

另一种班轮方式，

test_tweets.map {|tweet| tweet.gsub!(Regexp.union(banned_phrases),'censored')}

它使用正则表达式匹配那些被禁止的短语并全局替换它们

Ruby替换数组中的元素

2 个答案: