Question

我有两个雄辩的输出

allowance   Amount
A           100
B           80
C           120
D           150

AND

Deductions  Amount
X           50
Y           60
Z           70

和json显示为

$allowance = [{"allname":"A","allamount":"100"},{"allname":"B","allamount":"80"},{"allname":"C","allamount":"120"},{"allname":"D","allamount":"150"}]
$Deductions = [{"dedname":"X","dedamount":"50"},{"dedname":"Y","dedamount":"60"},{"dedname":"Z","dedamount":"70"}].

我希望新的json像

$new = [{"allname":"A","allamount":"100","dedname":"X","dedamount":"50"},{"allname":"B","allamount":"80","dedname":"Y","dedamount":"60"},{"allname":"C","allamount":"120","dedname":"Z","dedamount":"70"},{"allname":"D","allamount":"150"}]

请引导我。预先感谢。

Answer 1

假设您有两个收藏夹

$firstCollection = collect(['one','two']);

$collectionTwo = collect(['three','four']);

$firstCollection->merge($collectionTwo);

使用merge()将合并两个集合。

Answer 2

尝试以下代码即可获得所需的内容：

$a = array(array('allname'   =>'A','allamount'=>'100'),
           array('allname'   =>'B','allamount'=>'200'),
           array('allname'   =>'C','allamount'=>'300'));

$b = array(array('dedname'   =>'X','dedamount'=>'50'),
           array('dedname'   =>'c','dedamount'=>'150'));

$all=array();

for ($i=0; $i < count($a); $i++) { 

   $merged="";   

   if (isset($b[$i])) {

      $merged=array_merge($a[$i],$b[$i]);

   }else{

      $merged=$a[$i];
   }

   $all[]=$merged;
}

echo "<pre>";print_r($all);echo "<br";

header('Content-Type: application/json');

echo json_encode($all);

输出：

[{“ allname”：“ A”，“ allamount”：“ 100”，“ dedname”：“ X”，“ dedamount”：“ 50”}，{“ allname”：“ B”，“ allamount” ：“ 200”，“ dedname”：“ c”，“ dedamount”：“ 150”}，{“ allname”：“ C”，“ allamount”：“ 300”}]

希望这对您有所帮助。

合并口才结果集

2 个答案: