Question

可以使用tkinter treeview将文本换行吗？我试图更改行高，但文本不会自动换行。基本上我想在行中有多行文本。

这是代码：

from tkinter import*
from tkinter import ttk

myApp = Tk()


NewTree= ttk.Treeview(myApp, height=5)
NewTree['show'] = 'headings'
s = ttk.Style()
s.configure('Treeview', rowheight=40)

NewTree["columns"]=("1","2")

NewTree.column("1", width=60)
NewTree.column("2", width=60)

NewTree.heading("1", text="col a")
NewTree.heading("2", text="col b")

item = NewTree.insert("", "end", values=("i want to wrap this text","and this text"))

NewTree.grid(row=0,column=0)

myApp.mainloop()

这是代码的第二个版本（当您可以在treeview中手动添加项目时），它在我上面发布的代码之前仅具有一个重要功能。我试图在lenght上放置不同的值，但结果是相同的（不会自动换行）：

from tkinter import*
from tkinter import ttk
from tkinter import messagebox

import textwrap

def wrap(string, lenght=15):
    return '\n'.join(textwrap.wrap(string, lenght))

myApp = Tk()

def editact(event):

    def double(event): # funkcija koja kreira celiju kada se klikne dupli klik
        try:            
            if NewTree.identify_region(event.x, event.y) == 'cell':
                # the user clicked on a cell

                def ok(event):
                    """Change item value."""
                    NewTree.set(item, column, entry.get())
                    entry.destroy()

                column = NewTree.identify_column(event.x)  # identify column
                item = NewTree.identify_row(event.y)  # identify item
                x, y, width, height = NewTree.bbox(item, column) 
                value = NewTree.set(item, column)

            elif NewTree.identify_region(event.x, event.y) == 'heading': 
                    # the user clicked on a heading

                def ok(event):
                    """Change heading text."""
                    NewTree.heading(column, text=entry.get())
                    entry.destroy()

                column = NewTree.identify_column(event.x) # identify column
                # tree.bbox work only with items so we have to get the bbox of the heading differently
                x, y, width, _ = NewTree.bbox(NewTree.get_children('')[0], column) # get x and width (same as the one of any cell in the column)
                # get vertical coordinates (y1, y2)
                y2 = y
                # get bottom coordinate
                while NewTree.identify_region(event.x, y2) != 'heading':  
                    y2 -= 1
                # get top coordinate
                y1 = y2
                while NewTree.identify_region(event.x, y1) == 'heading':
                    y1 -= 1
                height = y2 - y1
                y = y1
                value = NewTree.heading(column, 'text')

            elif NewTree.identify_region(event.x, event.y) == 'nothing': 
                column = NewTree.identify_column(event.x) # identify column
                # check whether we are below the last row:
                x, y, width, height = NewTree.bbox(NewTree.get_children('')[-1], column)
                if event.y > y:

                    def ok(event):
                        """Change item value."""
                        # create item
                        item = NewTree.insert("", "end", values=("", ""))
                        NewTree.set(item, column, entry.get())
                        entry.destroy()

                    y += height
                    value = ""
                else:
                    return
            else:
                return

            # display the Entry   
            entry = ttk.Entry(NewTree)  # create edition entry
            entry.place(x=x, y=y, width=width, height=height, anchor='nw')  # display entry on top of cell
            entry.insert(0, value)  # put former value in entry
            entry.bind('<FocusOut>', ok)  #validate when you click on other cell

            entry.focus_set()

        except IndexError:

            Error=messagebox.showinfo("Error!","You have 0 rows. Please add a new row.")
            sys.exit() #za resavalje greske`
            pass

    NewTree.bind('<Double-Button-1>', double) #create new cell with double click


NewTree= ttk.Treeview(myApp, height=5)
NewTree['show'] = 'headings'

s = ttk.Style()
s.configure('Treeview', rowheight=60)

NewTree["columns"]=("1","2")

NewTree.column("1", width=100, anchor="center")
NewTree.column("2", width=100, anchor="w")

NewTree.heading("1", text="Col A")
NewTree.heading("2", text="Col B")


item = NewTree.insert("", "end", values=(wrap(""),wrap("")))
NewTree.item(item, tags=item)
NewTree.bind('<1>', editact)

NewTree.grid(row=0,column=0, columnspan=5, padx=5)

myApp.mainloop()

Answer 1

以下代码使用Entity事件动态包装文本（因此，支持调整列的大小，并且文本将相应地“包装”）。

<B1-Motion>

Answer 2

您可以使用textwrap模块来定义此wrap函数：

def wrap(string, lenght=8):
    return '\n'.join(textwrap.wrap(string, lenght))

现在，您可以将item替换为：

item = NewTree.insert("", "end", values=(wrap("i want to wrap this text"),
                                         wrap("and this text")))

完整代码

from tkinter import *
from tkinter import ttk

import textwrap


def wrap(string, lenght=8):
    return '\n'.join(textwrap.wrap(string, lenght))


myApp = Tk()

NewTree = ttk.Treeview(myApp, height=5)
NewTree['show'] = 'headings'
s = ttk.Style()
s.configure('Treeview', rowheight=40)

NewTree["columns"] = ("1", "2")

NewTree.column("1", width=60)
NewTree.column("2", width=60)

NewTree.heading("1", text="col a")
NewTree.heading("2", text="col b")

item = NewTree.insert("", "end", values=(wrap("i want to wrap this text"),
                                         wrap("and this text")))

NewTree.grid(row=0, column=0)

myApp.mainloop()

输出

Output

在tkinter treeview中的行内换行

2 个答案:

完整代码

输出