Question

我有一个页面“ elenco.php”，在其中显示了表中的所有数据库记录，并在末尾的每一行中都有一个“编辑”按钮，该按钮向页面“ edit.php”提交了“ ID”用户要编辑的行。

elenco.php

  <?php 
    include '/var/www/phpMyEdit/open_dati.php';


    $query = "SELECT * FROM scadenziario"; 
    $result= mysql_query($query);


    echo "<h2>Elenco Scadenziario</h2>";

        echo "<table border>";
            echo "<tr><td>ID</td><td>Aspetto Generale</td><td>Descrizione</td><td>Ragione Sociale</td><td>Numero Civico</td><td>Validita</td><td>Data</td><td>Preavviso</td><td>Scadenza</td><td>Prescrizioni</td><td>Frequenza</td><td>Data Controllo</td><td>Prossimo Controllo</td><td>Note</td>";
                while($row = mysql_fetch_array($result)){
                    echo "<tr><td>" . $row[ID] . 
                    "</td><td>". $row[Aspetto_Generale]. 
                    "</td><td>". $row[Descrizione].
                    "</td><td>". $row[Ragione_Sociale].
                    "</td><td>". $row[Num_Civico].
                    "</td><td>". $row[Validita].
                    "</td><td>". $row[Data].
                    "</td><td>". $row[Preavviso].
                    "</td><td>". $row[Scadenza].
                    "</td><td>". $row[Prescrizioni].
                    "</td><td>". $row[Frequenza].
                    "</td><td>". $row[Data_Controllo].
                    "</td><td>". $row[Prox_Controllo].
                    "</td><td>". $row[Note].
                    "</td><td><form action='edit.php' method='POST'><input type='hidden' name='tempID' value='".$row['ID']."'/><input type='submit' name='submit-btn' value='Edit' /><form></td></tr>";
                }
        echo "</table>";

    mysql_close();
    ?>

edit.php

 <?echo'
        <html>
        <head>
        <link rel="stylesheet" type="text/css" href="form.css">
        </head>';

        include '/var/www/phpMyEdit/open_dati.php';

        $temp = $_POST['tempID'];

        $query = "SELECT * FROM scadenziario WHERE ID = '$temp' "; 
        $result= mysql_query($query);

            while($row = mysql_fetch_array($result)){
                    $aspettogen = $row['Aspetto_Generale'];
                    $desc = $row['Descrizione'];
                    $ragsoc = $row['Ragione_Sociale'];
                    $numcivico = $row['Num_Civico'];
                    $validita = $row['Valdita'];
                    $odierna = $row['Data'];
                    $preavviso = $row['Preavviso'];
                    $scadenza = $row['Scadenza'];
                    $presc = $row['Prescrizioni'];
                    $freq = $row['Frequenza'];
                    $datacontr = $row['Data_Controllo'];
                    $proxcontr = $row['Prox_Controllo'];
                    $note = $row['Note'];
            }?>



    <? echo'
        <body>
            <div class="container">  
                <form id="contact" method="POST">'?>



                <? echo'
                                <img src="logo.jpg"> 
                                <fieldset>
                                <input name="aspettogen2" type="text" value="'.$aspettogen.'">
                                </fieldset>
                                <fieldset>
                                    <input name="desc" type="text" maxlength="255" value="'.$desc.'">
                                </fieldset>
                                <fieldset>
                                    <input name="ragsoc" type="text" maxlength="100">
                                </fieldset>
                                <fieldset>
                                    <input name="numcivico"  type="text" maxlength="20">
                                </fieldset>
                                <fieldset>
                                    <input name="validita" type="text">
                                </fieldset>
                                <fieldset>
                                    <input name="odierna" type="data">
                                </fieldset>
                                <fieldset>
                                    <input name="preavviso" type="text">
                                </fieldset>
                                <fieldset>
                                    <input name="scadenza" type="text">
                                </fieldset>
                                <fieldset>
                                    <input name="presc" type="text" maxlength="255">
                                </fieldset>
                                <fieldset>
                                    <input name="freq" type="number">
                                </fieldset>
                                <fieldset>
                                    <input name="datacontr" type="text">
                                </fieldset>
                                <fieldset>
                                    <input name="proxcontr" type="text">
                                </fieldset>
                                <fieldset>
                                    <input name="note" type="text">
                                </fieldset>             
                            </form>
                        </div>
                    </body>
                </html>';

    mysql_close(); 
    ?>

但是我不明白为什么在页面edit.php中，id值始终是表DB的最后一条记录。

例如，我的表有35条记录，如果我单击页面“ elenco.php”中第10行的编辑按钮，则在页edit.php中，我始终收到ID = 35（数据库的最后一条记录）

你能帮我吗？

Answer 1

在elenco.php和edit.php中将mysql *函数替换为mysqli *函数。

然后检查post数组中的所有内容，并确保使用来获取所有数据

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<form action='#' method='post' id="4" class='item'>
  <div class='item-edit' data-type='fileArray' data-name='file[]' data-maxFiles='1'>LOGO HERE</div>
  <div class='item-edit' data-type='input' data-name='agnt[name]' data-require='1'>SOME NAME</div>
  <div class='item-edit' data-type='textarea' data-name='agnt[contact]'>SOME CONTACT</div>
  <div class='col-md-2 panel-menu'>
    <span class='edit_msg'></span>

    <a href='#' class='btn btn-success edit_save-btn hidden'>SAVE</a>
    <a href='#' class='btn btn-success edit-btn'>EDIT</a>

  </div>
</form>

和此代码：

var_dump($_POST);

我假设您的id是整数类型，因此您不必使用''，请尝试：

$query = "SELECT * FROM scadenziario WHERE ID = '$temp' ";

希望这会有所帮助。

从表单PHP更新记录数据库

1 个答案: