我有一个带account_type属性的“用户”或“合作伙伴”用户模型。我在用户模型中创建了布尔方法,以确定用户记录是学生还是合伙人(请参见下文)。
def student?
self.account_type == "Student"
end
def partner?
self.account_type == "Partner"
end
在Rails控制台中,当我将user设置为具有学生帐户类型的User实例并输入user.account_type ==“ Student”时,我为true,但是当我调用user.student?时,我为false。我如何设置这些方法是否有问题?它们看起来很简单,所以我不理解为什么记录没有返回true。
控制台输出:
user = User.last
#<User id: 18, first_name: "gjalrgkj", last_name: "kgjrlgakjrl", email: "terajglrkj@gmail.com", password_digest: "$2a$10$WF.Rw3PzlWilH0X.Nbfxfe5aB18WW6J7Rt4SAKQEwI8...", remember_digest: nil, activation_digest: "$2a$10$/bXG4/nKCiiZHWailUPAmOZj7YhCjKhPm4lUW6nPC3N...", activated: nil, activated_at: nil, reset_digest: nil, reset_sent_at: nil, account_type: "Student", created_at: "2018-07-02 04:21:07", updated_at: "2018-07-02 04:21:07">
>> user.account_type
=> "Student"
>> user.account_type = "Student"
=> "Student"
>> user.student?
=> false
用户模型:
class User < ApplicationRecord
has_one :personal_information
attr_accessor :remember_token, :activation_token, :reset_token
before_save :downcase_email
before_create :create_activation_digest
validates :first_name, presence: true, length: { maximum: 50 }
validates :last_name, presence: true, length: { maximum: 50 }
VALID_EMAIL_REGEX = /\A[\w+\-.]+@[a-z\d\-]+(\.[a-z\d\-]+)*\.[a-z]+\z/i
validates :email, presence: true, length: { maximum: 255 },
format: { with: VALID_EMAIL_REGEX },
uniqueness: { case_sensitive: false }
has_secure_password
validates :password, presence: true, length: { minimum: 6 }, allow_nil: true
validates :account_type, presence: true
def User.new_token
SecureRandom.urlsafe_base64
end
def User.digest(string)
cost = ActiveModel::SecurePassword.min_cost BCrypt::Engine::MIN_COST :
BCrypt::Engine.cost
BCrypt::Password.create(string, cost: cost)
end
def create_reset_digest
self.reset_token = User.new_token
update_columns(reset_digest: User.digest(reset_token), reset_sent_at: Time.zone.now)
end
def authenticated?(attribute, token)
return false if digest.nil?
BCrypt::Password.new(digest).is_password?(token)
end
def remember
self.remember_token = User.new_token
update_attribute(:remember_digest, User.digest(remember_token))
end
def forget
update_attribute(:remember_digest, nil)
end
def provide_age
now = Time.now.utc.to_date
if self.birthday.nil?
nil
else
self.age = now.year - self.birthday.year - ((now.month > self.birthday.month || (now.month == self.birthday.month && now.day >= self.birthday.day)) ? 0 : 1)
update_attribute(:age, self.age)
end
end
def send_activation_email
UserMailer.account_activation(self).deliver_now
end
def activate
update_columns(activated: true, activated_at: Time.zone.now)
end
def send_password_reset_email
UserMailer.password_reset(self).deliver_now
end
def password_reset_expired?
reset_sent_at < 2.hours.ago
end
private
def downcase_email
self.email.downcase!
end
def create_activation_digest
self.activation_token = User.new_token
self.activation_digest = User.digest(activation_token)
end
end
用户助手
def account_type
[
['Student'],
['Partner'],
['School Administrator'],
['Philanthropist']
]
end
def student?
self.account_type == "Student"
end
def partner?
self.account_type == "Partner"
end
end
答案 0 :(得分:3)
您的2种方法partner?
和user.student?
属于用户模型。
在执行student?
时,它将在用户模型中寻找self
方法作为实例方法。
app.service('searchService', function() {
this.searchState={
loading: false,
data: null,
error: null
}
this.fetchSearchResults = function(key){
// call api methods to get response
// can be via callbacks or promise.
this.searchState.loading=true;
someMethodThatCallsApi(key)
.then(function(success){
this.searchState.loading=false;
this.searchState.data=success;
this.searchState.error=null
})
.catch(function(error){
this.searchState.loading=false;
this.searchState.data=null;
this.searchState.error=error
});
}
this.getState = function(){
return this.searchState
}
});
不是它指向您的帮助器模块的用户实例。
希望这会有所帮助。
答案 1 :(得分:0)
尝试将此代码放入用户模型(不在Helper中)
def student?
self.account_type == "Student"
end
def partner?
self.account_type == "Partner"
end
这是一个创建设置器以设置account_type(例如)的好主意
def set_account_type(type)
self.account_type = type
end