在我的项目中,我正在使用recompose / react-google-maps定义顶级组件,如下所示:
const LocationPicker = compose(
withProps({
googleMapURL: "https://maps.googleapis.com/maps/api/js?v=3.exp&libraries=geometry,places&key=AIzaSyDnKwHUG_EJXN5EEW6hTftZHYo8E8QTTXY",
loadingElement: <div style={{ height: `100%` }} />,
containerElement: <div style={{ height: `400px` }} />,
mapElement: <div style={{ height: `100%` }} />,
}),
withScriptjs,
withGoogleMap,
withState('places', '', ''),
withHandlers(() => {
refs = {
map: undefined,
}
return {
onMapMounted: () => ref => {
refs.map = ref
service = new google.maps.places.PlacesService(refs.map.context.__SECRET_MAP_DO_NOT_USE_OR_YOU_WILL_BE_FIRED);
},
}
}),
)((props) => {
return (
<GoogleMap
ref={props.onMapMounted}
defaultZoom={13}
defaultCenter={{ lat: 42.3570637, lng: -71.06257679999999 }}
>
{props.marker &&
<Marker position={{ lat: props.marker.lat, lng: props.marker.lng }} draggable={true} />
}
</GoogleMap>
)
})
这是在类范围之外定义的Component。我收到以下错误:
TypeError: Object(...) is not a function
为什么不能这样定义组件?
答案 0 :(得分:1)
首先,我将其分解为无状态功能组件,然后使用Recompose增强该组件。
const LocationPickerView = props => (
<GoogleMap
ref={props.onMapMounted}
defaultZoom={13}
defaultCenter={{ lat: 42.3570637, lng: -71.06257679999999 }}
>
{props.marker && (
<Marker position={{ lat: props.marker.lat, lng: props.marker.lng }} draggable />
)}
</GoogleMap>
);
const LocationPicker = compose(
withProps({
googleMapURL:
'https://maps.googleapis.com/maps/api/js?v=3.exp&libraries=geometry,places&key=AIzaSyDnKwHUG_EJXN5EEW6hTftZHYo8E8QTTXY',
loadingElement: <div style={{ height: '100%' }} />,
containerElement: <div style={{ height: '400px' }} />,
mapElement: <div style={{ height: '100%' }} />
}),
withScriptjs,
withGoogleMap,
withState('places', '', ''),
withHandlers(() => {
refs = {
map: undefined
};
return {
onMapMounted: () => ref => {
refs.map = ref;
service = new google.maps.places.PlacesService(
refs.map.context.__SECRET_MAP_DO_NOT_USE_OR_YOU_WILL_BE_FIRED
);
}
};
})
)(LocationPickerView);
我认为这可以解决您的TypeError
。
如果不是,请尝试注释掉ref
和withHandler
部分。您可能在那里有单独的问题。