Question

我要做的是将文件从一个位置更改为另一个位置。

这是代码：

print ("Loading system, please wait 5 seconds.")

try:
    import os, sys
    # Path to be created
    path = "C:\Windows2" # Just a testing random file...
    os.mkdir( path, 0755 );

except:
    print 'Path already created. Passing...'


import shutil
src = data_path =  os.path.expanduser('~')+ '\Desktop\admin.dll'
dst = data_path = "C:\Windows2"
shutil.move(src, dst)

但是，然后出现以下错误：

Traceback (most recent call last):
  File "C:\Users\youse\Desktop\TESTING.py", line 16, in <module>
    shutil.move(src, dst)
  File "C:\Python27\lib\shutil.py", line 316, in move
    copy2(src, real_dst)
  File "C:\Python27\lib\shutil.py", line 144, in copy2
    copyfile(src, dst)
  File "C:\Python27\lib\shutil.py", line 96, in copyfile
    with open(src, 'rb') as fsrc:
IOError: [Errno 22] invalid mode ('rb') or filename: 'C:\\Users\\youse\\Desktop\x07dmin.dll'
>>>

Answer 1

您需要使用双反斜杠在带引号的字符串中表示文字反斜杠。

src = data_path =  os.path.expanduser('~')+ '\\Desktop\\admin.dll'
dst = data_path = "C:\\Windows2"

使用open（src，'rb'）作为fsrc：IOError：[Errno 22]无效模式（'rb'）或文件名：

1 个答案: