Question

我可能是javascript新手，我想以json对象格式从表中提取数据我的桌子看起来像这样

<table>
<thead>
<tr>
<th class="active">Bolumn</th>
<th class="active">Column</th>
<th class="active">Dolumn</th>
<th>Molumn</th>
</tr>
</thead>
<tbody>
<tr>
<td class="active">Bolumn Data</td>
<td class="active">Column Data</td>
<td class="active">Dolumn Data</td>
<td>Molumn Data</td>
</tr>
<tr>
<td class="active">Bolumn Data 1</td>
<td class="active">Column Data 1</td>
<td class="active">Dolumn Data 1</td>
 <td>Molumn Data 1</td>
</tr>
<tr>
<td class="active">Bolumn Data 2</td>
<td class="active">Column Data 2</td>
<td class="active">Dolumn Data 2</td>
<td>Molumn Data 2</td>
</tr>
</tbody>
</table>

在表中，有些具有活动类，我只需要该活动类数据

所以我想要json格式的样子，我想要使用jquery方法

[{"Bolumn":"Bolumn Data","Column":"Column Data","Dolumn":"Dolumn Data"},
{"Bolumn":"Bolumn Data 1","Column":"Column Data 1","Dolumn":"Dolumn Data 1"},
{"Bolumn":"Bolumn Data 2","Column":"Column Data 2","Dolumn":"Dolumn Data 2"}]

预先感谢

已更新：我已经尝试过像这样的代码，但是我不知道如何实现

var array = [];
$('tr').each(function (i) {
    $(this).find('td').each(function (i) {
        if ($(this).hasClass('active')) {
            array.push($(this).text());
        }
    });
});

Answer 1

您的代码已接近正常工作。它需要一些东西才能获得您想要的结果。首先，由于需要对象，因此需要在标题中找到的键。您可以像处理数据一样制作这些数组：

var headers = []
$('tr th').each(function (i) {
    headers.push($(this).text())
})

现在，您可以在循环中按索引引用标头，并在操作时为键分配值：

// find headers
var headers = []
$('tr th').each(function(i) {
  headers.push($(this).text())
})
// result array
var array = [];
$('tr').each(function(i) {
  // declare object variable but dont set it's value
  // unless there are objects to find
  var rowObj
  $(this).find('td').each(function(i) {
    if (!rowObj) rowObj = {}
    if ($(this).hasClass('active')) {
      // use the header we found earlier
      rowObj[headers[i]] = $(this).text()
    }
  });
  // if we found active objects, rowObje will be defined
  if (rowObj) array.push(rowObj)
});
console.log(array)

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
  <thead>
    <tr>
      <th class="active">Bolumn</th>
      <th class="active">Column</th>
      <th class="active">Dolumn</th>
      <th>Molumn</th>
    </tr>
  </thead>
  <tbody>
    <tr>
      <td class="active">Bolumn Data</td>
      <td class="active">Column Data</td>
      <td class="active">Dolumn Data</td>
      <td>Molumn Data</td>
    </tr>
    <tr>
      <td class="active">Bolumn Data 1</td>
      <td class="active">Column Data 1</td>
      <td class="active">Dolumn Data 1</td>
      <td>Molumn Data 1</td>
    </tr>
    <tr>
      <td class="active">Bolumn Data 2</td>
      <td class="active">Column Data 2</td>
      <td class="active">Dolumn Data 2</td>
      <td>Molumn Data 2</td>
    </tr>
  </tbody>
</table>

Answer 2

作为jQuery解决方案的替代方法，这里有使用Array.prototype.map和Array.prototype.reduce的香草js和ES6。

学习这些内容将来会很有用，并将帮助您编写更多声明性代码。

// 1) extract headers and rows in separate arrays with 
//    respective `isActive` flag for each item in both

var [headers, ...rows] = [...document.querySelectorAll('tr')].map(
  tr =>  [...tr.querySelectorAll('*')].map(n => ({
  name: n.innerText,
  isActive: n.classList.contains('active')
})));

// 2) iterate over the `rows` and dynamically aggregate the output object 
//    by matching headers and rows based on their indexes:

var result = rows.map(row => {
  return headers.reduce((obj, h, j) => {
    if (h.isActive && row[j].isActive) {
      obj[h.name] = row[j].name;
    }
    return obj;
  }, {});
});
console.log(result);

<table>
  <thead>
    <tr>
      <th class="active">Bolumn</th>
      <th class="active">Column</th>
      <th class="active">Dolumn</th>
      <th>Molumn</th>
    </tr>
  </thead>
  <tbody>
    <tr>
      <td class="active">Bolumn Data</td>
      <td class="active">Column Data</td>
      <td class="active">Dolumn Data</td>
      <td>Molumn Data</td>
    </tr>
    <tr>
      <td class="active">Bolumn Data 1</td>
      <td class="active">Column Data 1</td>
      <td class="active">Dolumn Data 1</td>
      <td>Molumn Data 1</td>
    </tr>
    <tr>
      <td class="active">Bolumn Data 2</td>
      <td class="active">Column Data 2</td>
      <td class="active">Dolumn Data 2</td>
      <td>Molumn Data 2</td>
    </tr>
  </tbody>
</table>

从表数据获取Javascript对象数组

2 个答案: