我只能用以下代码绘制条形图,而不是按发生的日期对所有案件进行分组:
trace1=go.Bar(
x=pd.to_datetime(dfb['date']),
y=dfb.set_index('date').resample('M')["enrolled"].sum(),
)
如何按日期分组? 数据集如下
date enrolled
6/29/2018 1
6/29/2018 1
6/29/2018
6/29/2018 1
6/20/2018 1
6/22/2018 1
6/19/2018 1
6/27/2018 1
6/28/2018
6/27/2018 1
6/19/2018 1
6/20/2018 1
6/27/2018 1
6/27/2018
6/26/2018 1
6/27/2018
6/27/2018 1
谢谢
答案 0 :(得分:0)
我在data.csv
中使用了以下内容:
date enrolled
6/29/2018 1
6/29/2018 1
6/29/2018 0
6/29/2018 1
6/20/2018 1
6/22/2018 1
6/19/2018 1
6/27/2018 1
6/28/2018 0
6/27/2018 1
6/19/2018 1
6/20/2018 1
6/27/2018 1
6/27/2018 0
6/26/2018 1
6/27/2018 0
6/27/2018 1
这是针对您的问题的一种可能解决方案:
import plotly
import plotly.graph_objs as go
import pandas as pd
# Read in data (might be already given in your code)
df = pd.read_csv('data.csv', delimiter=' ')
groups = df.groupby(['date'])
xData = []
yData = []
# Group data by keys and get sum
for group, data in df.groupby(['date']):
xData.append(group)
yData.append(data['enrolled'].sum())
data = [go.Bar(
x=xData,
y=yData
)]
plotly.offline.plot(data, filename='a-simple-plot')
此示例使用破折号发布图形:
import pandas as pd
# Read in data (might be already given in your code)
df = pd.read_csv('data.csv', delimiter=' ')
groups = df.groupby(['date'])
xData = []
yData = []
# Group data by keys and get sum
for group, data in df.groupby(['date']):
xData.append(group)
yData.append(data['enrolled'].sum())
# Dash specific stuff
import dash
import dash_core_components as dcc
import dash_html_components as html
app = dash.Dash()
app.layout = html.Div(children=[
html.H1(
children='Hello Dash',
),
html.Div(children='Dash: A web application framework for Python.', style={
'textAlign': 'center'
}),
dcc.Graph(
id='example-graph-2',
figure={
'data': [
{'x':xData, 'y': yData, 'type': 'bar'},
],
'layout': {}
}
)
])
if __name__ == '__main__':
app.run_server(debug=True)
答案 1 :(得分:0)
`:a/b/fileA/fileB/fileC`:c/d/fileX/fileY
答案 2 :(得分:0)
nodes