Question

此迁移为：

Schema::create('user_tickets', function (Blueprint $table) {
    $table->increments('id');
    $table->integer('user_id')->unsigned();
    $table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');
    $table->string('subject');
    $table->integer('ticket_number')->unique();
    $table->tinyInteger('priority')->default(2);
    $table->tinyInteger('section');
    $table->boolean('solved')->default(false);
    $table->timestamps();
});

和

Schema::create('user_tickets_answers', function (Blueprint $table) {
    $table->increments('id');
    $table->integer('user_id')->unsigned();
    $table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');
    $table->integer('ticket_id')->unsigned();
    $table->foreign('ticket_id')->references('id')->on('user_tickets')->onDelete('cascade');
    $table->text('reply',200);
    $table->timestamps();
});

laravel为我创建此外键

user_tickets_answers_user_id_foreign
user_tickets_answers_ticket_id_foreign

在user_tickets_answers表上，现在当我尝试获取具有user_tickets关系的user_tickets_answers数据时，例如：

$tickets = UserTickets::with('reply')->get();

我收到此错误：

Base table or view not found: 1146 Table 'diabet.user_ticket_answers' doesn't exist (SQL: select * from `user_ticket_answers` where `user_ticket_answers`.`ticket_id` in (1))

如何在自模型中定义此外键？

UserTickets：

class UserTickets extends Model
{
    protected $guarded = ['id'];

    public function reply()
    {
        return $this->hasMany(UserTicketAnswers::class, 'ticket_id');
    }
}

UserTicketAnswers：

class UserTicketAnswers extends Model
{
    protected $guarded = ['id'];

    public function ticket()
    {
        return $this->belongsTo(UserTickets::class);
    }
}

Answer 1

尝试更改该语句（如果可行），因为以前发生此错误时，它对我有用。可以肯定的是，再次检查Documentation，以传递自定义键，例如

（'App \ Phone'，'foreign_key'，'local_key'）;

在UserTickets模型更改中

return $this->hasMany(UserTicketAnswers::class, 'ticket_id');

到

return $this->hasMany('App\UserTicketAnswers','ticket_id','id');

在UserTicketAnswers

return $this->belongsTo(UserTickets::class);

到

return $this->belongsTo('App\UserTickets','ticket_id','ticket_id');

与您的User模型相同的逻辑。

public function userTickets(){
    return $this->hasMany('App\UserTickets','user_id','id');
}

public function userTicketAnswers(){
    return $this->hasMany('App\UserTicketAnswers','user_id','id');
}

将它们分别添加到UserTickets和UserTicketAnswers模型中

public function user{
    return $this->belongsTo('App\Users','user_id','user_id');
}

Answer 2

您的表名称在迁移中有所不同，在查询数据库中的 user_tickets_answers 表时，它是 user_tickets_answers 。

Laravel在模型中定义多个foregin键并出现错误

2 个答案: