Question

我想选择所有td所单击的tr，只有td具有输入复选框。以下代码使我无法选择具有输入字段的td：

$(".table-row td:not(:has(input))").click(function(){...}

但是我无法访问其他td的值。

是什么原因引起的问题？如何选择除特定td之外的所有td？

.html

<tr data-id="{{ test.id }}" class="table-row">
 <td class="form-check">
  <div class="form-check">
   <label class="form-check-label">
    <input class="form-check-input check-ele check-prevent" type="checkbox" value="">
    <span class="form-check-sign">
     <span class="check"></span>
    </span>
   </label>
  </div>
 </td>
 <td>{{ forloop.counter }}</td>
 <td name="test_name">{{ test.test_name}}</td>
 <td name="test_type">{{ test.test_type}}</td>
 <td name="test_date">{{ test.test_date|date:"m/d/Y" }}</td>  
</tr>

jQuery

$(".table-row td:not(:has(input))").click(function(){
  $('#editModal').modal('show');
  let row = $(this).closest('tr').attr('data-id');
  var test_name = $(this).find('td[ name="test_name" ]').text();
  console.log(typeof(test_name));
  // return empty test_name. The row I click on has test_name with value `Entrance Exam`
  var test_type = $(this).find('td[ name="test_type" ]').text();
  var test_date = $(this).find('td[ name="test_date" ]').text();
  var date = new Date(test_date);
  var day = ("0" + date.getDate()).slice(-2);
  var month = ("0" + (date.getMonth() + 1)).slice(-2);
  var test_date = date.getFullYear()+"-"+(month)+"-"+(day) ;
  $('#edit_test_date').val(test_date);
  $("#edit_test_name").val(test_name);
  $("#edit_test_type").val(test_type);

Answer 1

您的选择器工作正常，如下面的示例所示，但是您错误地访问了其他<td>的值。这是另一种方法：

const cells = $(".table-row td:not(:has(input))");

cells.click((e) => {
  const row = e.target.parentElement;
  const [ name, type, date ] = Array.from(row.children).slice(2).map(cell => cell.getAttribute('name'));
  
  console.log(`NAME = ${ name }, TYPE = ${ type }, DATE = ${ date }`)
});

table {
  border-collapse: collapse;
  border: 3px solid black;
  width: 100%;
  text-align: center;
  font-family: monospace;
}

td {
  padding: 10px 20px;
}

td:not(:first-child) {
  cursor: pointer;
  border-left: 3px solid black;
}

td:not(:first-child):hover {
  background: yellow;
}

.as-console-wrapper {
  max-height: 44px !important;
}

<table>
  <tr class="table-row">
    <td>
      <div>
        <label>
          <input type="checkbox" value="">
        </label>
      </div>
    </td>
    <td name="counter1">Counter 1</td>
    <td name="name1">Name 1</td>
    <td name="type1">Type 1</td>
    <td name="date1">Date 1</td>  
  </tr>
  
  <tr class="table-row">
    <td>
      <div>
        <label>
          <input type="checkbox" value="">
        </label>
      </div>
    </td>
    <td name="counter2">Counter 2</td>
    <td name="name2">Name 2</td>
    <td name="type2">Type 2</td>
    <td name="date2">Date 2</td>  
  </tr>
  
  <tr class="table-row">
    <td>
      <div>
        <label>
          <input type="checkbox" value="">
        </label>
      </div>
    </td>
    <td name="counter3">Counter 3</td>
    <td name="name3">Name 3</td>
    <td name="type3">Type 3</td>
    <td name="date3">Date 3</td>  
  </tr>
</table>

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

您的代码中的问题在这里：

let row = $(this).closest('tr').attr('data-id');
var test_name = $(this).find('td[ name="test_name" ]').text();

您应该选择实际的行（<tr>而不是其data-id属性，然后使用该row查找不同的单元格及其{{1}的值}属性：

name

jQuery：选择除特定“”以外的所有“”

1 个答案: