我的项目是保存裁切后的图像并在视图中显示。
当我裁剪图像时,它以我的形式工作,但是当我想更改图像时,我再次裁剪并保存。它创建具有相同图像的两行。 当我将图像更改3次时,它会用相同的图像创建3行,依此类推。
有一个我必须使用的方法称为replace(),但我不知道如何使用它。
这是我的代码
window.addEventListener('DOMContentLoaded', function () {
var avatar = document.getElementById('avatar');
var image = document.getElementById('image');
var input = document.getElementById('input');
var $progress = $('.progress');
var $progressBar = $('.progress-bar');
var $alert = $('.alert');
var $modal = $('#modal');
var cropper;
var title = $('#title');
var description = $('#description');
var arabic_title = $('#arabic_title');
var arabic_description = $('#arabic_description');
$('[data-toggle="tooltip"]').tooltip();
input.addEventListener('change', function (e) {
var files = e.target.files;
var done = function (url) {
input.value = '';
image.src = url;
// $alert.hide();
$modal.modal('show');
};
var reader;
var file;
var url;
if (files && files.length > 0) {
file = files[0];
if (FileReader) {
reader = new FileReader();
reader.onload = function (e) {
done(reader.result);
console.log('ok2');
};
reader.readAsDataURL(file);
console.log('ok3');
}
}
});
$modal.on('shown.bs.modal', function () {
cropper = new Cropper(image, {
aspectRatio: 1.7,
viewMode: 3,
});
}).on('hidden.bs.modal', function () {
cropper.destroy();
cropper = null;
});
document.getElementById('crop').addEventListener('click', function () {
var initialAvatarURL;
var canvas;
$modal.modal('hide');
if (cropper) {
canvas = cropper.getCroppedCanvas({
width: 400,
height: 400,
});
initialAvatarURL = avatar.src;
avatar.src = canvas.toDataURL();
$progress.show();
$alert.removeClass('alert-success alert-warning');
document.getElementById('save').addEventListener('click', function () {
canvas.toBlob(function (blob) {
var formData = new FormData();
formData.append('avatar', blob);
formData.append('title', title.val());
formData.append('description', description.val());
formData.append('arabic_title', arabic_title.val());
formData.append('arabic_description', arabic_description.val());
if (title.val() !== '' && description.val() !== '' && arabic_title.val() !== '' && arabic_description.val() !== '') {
for (let pair of formData.entries()) {
console.log(pair[0] + ', ' + pair[1]);
}
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}
});
$.ajax("{{url('admin/services')}}", {
method: 'POST',
data: formData,
processData: false,
contentType: false,
xhr: function () {
var xhr = new XMLHttpRequest();
xhr.upload.onprogress = function (e) {
var percent = '0';
var percentage = '0%';
if (e.lengthComputable) {
percent = Math.round((e.loaded / e.total) * 100);
percentage = percent + '%';
$progressBar.width(percentage).attr('aria-valuenow', percent).text(percentage);
}
};
return xhr;
},
success: function (data) {
$alert.show().addClass('alert-success').text('Upload success');
console.log(data);
},
error: function (error) {
avatar.src = initialAvatarURL;
$alert.show().addClass('alert-warning').text('Upload error');
console.log(error);
},
complete: function () {
$progress.hide();
},
});
}
});
});
}
});
});
答案 0 :(得分:0)
$service = 'No service';
if (isset($_FILES['img'])) {
$service = Service::create(['title'=>$request->title,
'description'=>$request->description,
'photo'=>$request->img]);
}
return $service;
尝试一下。
答案 1 :(得分:0)
您的表格应该是
<form action="files/upload" method="post" enctype="multipart/form-data">
<input type="file" name="photo"/>
</form
您的控制器应该像
if ($request->hasFile('photo')) {
// move file upload here
}