Question

在我的应用程序中，我想将AVAudioPlayer集成到我的应用程序中。但是我什么都不能。那就是我的代码：

import UIKit
import AVFoundation

class NotenAnsicht: UIViewController{


var PlaybackPlayer:AVAudioPlayer = AVAudioPlayer()


override func viewDidLoad() {
    super.viewDidLoad()
    PlaybackAudioAufsetzen()   
}




func PlaybackAudioAufsetzen(){

    do{

        let audioPath = Bundle.main.path(forResource: "song", ofType: "mp3")
        try PlaybackPlayer = AVAudioPlayer(contentsOf: NSURL(fileURLWithPath: audioPath!) as URL)
        print("Song set")
    }
    catch{
        print("there was an Error")

    }

}




override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}



@objc func PlaybayStarten(sender:UIButton){
    PlaybackPlayer.play()
    PlaybackPlayer.volume = 1
     print(PlaybackPlayer.isPlaying)
    print("Song should play")  
}


}

我不知道问题出在哪里。正确调用所有函数。并且音频播放器未在本地定义。在PlaybackPlayer.play()之后，PlaybackPlayer.isPlaying返回true。我什么都不能在这里。

您知道问题出在哪里吗？

Answer 1

在设置audioPath之前在您的do块中设置try AVAudioSession.sharedInstance().setCategory(AVAudioSessionCategoryPlayback)和try AVAudioSession.sharedInstance().setActive(true)。

您的代码应该看起来像这样。

func PlaybackAudioAufsetzen(){

    do{

        let audioPath = Bundle.main.path(forResource: "song", ofType: "mp3")

        /// this code will make this app ready to takeover the device audio
        try AVAudioSession.sharedInstance().setCategory(AVAudioSessionCategoryPlayback)
        try AVAudioSession.sharedInstance().setActive(true)

        try PlaybackPlayer = AVAudioPlayer(contentsOf: NSURL(fileURLWithPath: audioPath!) as URL)
        print("Song set")
    }
    catch let error {
        print(error.localizedDescription)
    }

}

AVAudioPlayer无法快速播放。如何解决？

1 个答案: