Question

这是我在这里的第一篇文章：）这是我做过的第一个python。我正在尝试编写一个脚本，该脚本在运行时将发送电子邮件。关于此电子邮件，对我来说有3件重要的事情：

1）没有“收件人”，只有“抄送”和“密件抄送”。

2）密件抄送-密件抄送下有很多地址，所有地址都必须获得电子邮件，但其他电子邮件地址必须隐藏。

3）我想为一个单词添加超链接。

我尝试使用MIMEMultipart，但是我找不到想让BCC正常工作的方法（我遍及google和stackoverflow都无法正常工作）。我能够实现发送带有隐藏的密件抄送功能的电子邮件，以便按我的意愿工作，但是它不使用MIMEMultipart-仅使用smtplib，但是我似乎不明白如何集成html部分。

def send_email():
password = '*********'
bcc = ['danielofir8@gmail.com','danielofirpython@gmail.com']
from_addr = 'danielofirsales@gmail.com'
to_addr = ''
cc_addr = 'danielofirsales@gmail.com'
mail_subject = "Testing E-mail"
content = "Maintenance on the New York data center will be performed on Sunday, July 1st, 2018 at 06:30 UTC.\nWe expect to complete the maintenance by Sunday, July 1st, 2018 at 08:30 "

body = f"From: {from_addr}\r\n" + f"To: {to_addr}\r\n" + f"Cc: {cc_addr}\r\n" + f"Subject: {mail_subject}\r\n" + "\r\n"  + content
to_addr = [to_addr] + [cc_addr] + bcc

try:
    server = smtplib.SMTP('smtp.gmail.com', 587)
    server.ehlo()
    server.starttls()
    server.login('danielofirsales@gmail.com',password)
    server.sendmail(from_addr, to_addr ,body)
    server.quit()
    print("Success")
except:
    print("Failed")
send_email()

我找到了一个人在这里写的关于如何使用MIMEMultipart在电子邮件中发送HTML的代码，并且能够发送带有超链接的电子邮件，但是每次尝试添加密件抄送时（我发现了几种不同的方式）在线），出现错误。

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
password = '*******'
from_adr='danielofirsales@gmail.com'
to_adr='danielofirpython@gmail.com'

msg = MIMEMultipart('alternative')
msg['Subject'] = "Emailing a link"
msg['From'] = 'danielofirsales@gmail.com'
msg['To'] = 'danielofirpython@gmail.com'

html = """
<html>
<head></head>
  <body>
    <p>Maintenance on the New York data center will be performed on Sunday, July 1st, 2018 at 06:30 UTC.\nAs published on our
    <a href="http://www.google.com">Status Page</a> - We expect to complete the maintenance by Sunday, July 1st, 2018 at 08:30</p>
  </body>
</html>
"""

part1=MIMEText(html, 'html')
part2=MIMEText("Maintenance on the New York data center will be performed on Sunday, July 1st, 2018 at 06:30 UTC.\nAs published on our http://www.google.com - We expect to complete the maintenance by Sunday, July 1st, 2018 at 08:30", 'text')

msg.attach(part1)
msg.attach(part2)


server = smtplib.SMTP('smtp.gmail.com', 587)
server.ehlo()
server.starttls()
server.login('danielofirsales@gmail.com',password)
server.sendmail(msg['From'], msg['To'] ,msg.as_string())
server.quit()
print("Success")

是否可以使用smtplib的隐藏BCC选项和MIMEMultipart的html选项？

同样重要的是，当前该脚本应通过Gmail发送电子邮件，但在实际应用时，它将从公司的电子邮件服务器发送电子邮件。

感谢您的帮助：）

丹尼尔。

Answer 1

好的，所以我能够找到某种方式来实现自己想要的东西。基本上，“困难”部分是使用MIMETEXT也以smtplib格式添加侦听器。（标题）希望这对以后的人有所帮助：）

def send_mail():
pop_input= input("Please write the PoP's name: ")
password = '*******'



from_adr='danielofirsales@gmail.com'
cc_adr='danielofirsales@gmail.com'
to_adr = ''
mail_subject = ''

msg = MIMEMultipart('alternative')
msg['Subject'] = f"Planned Maintenance on the {pop_input} PoP"
msg['From'] = 'danielofirsales@gmail.com'
msg['Cc'] = 'danielofirsales@gmail.com'

content = f"As published on our https://www.google.com, a maintenance on {pop_input}."
html = """
<html>
<head></head>
  <body>
    <p>As published on our
    <a href="https://www.google.com">Status Page</a>, a maintenance on {POP}</p>
  </body>
</html>
"""
new_html = html.format(POP=pop_input,START_TIME=start_message,END_TIME=end_message)
header = MIMEText(f"From: {from_adr}\r\n" + f"Cc: {cc_adr}\r\n" + f"Subject: {mail_subject}\r\n" + "\r\n",'plain') 


bcc = ['danielofir8@gmail.com','danielofirpython@gmail.com']
to_adr = [to_adr] + [cc_adr] + bcc

part1=MIMEText(new_html, 'html')
part2=MIMEText(content, 'text')

msg.attach(header)
msg.attach(part1)
msg.attach(part2)

try:
    server = smtplib.SMTP('smtp.gmail.com', 587)
    server.ehlo()
    server.starttls()
    server.login('danielofirsales@gmail.com',password)
    server.sendmail(from_adr, to_adr ,msg.as_string())
    server.quit()
    print("Success")
except:
    print("Failed")

如何发送带有隐藏的密件抄送和HTML内容的电子邮件

1 个答案: