Question

let backButton = UIBarButtonItem(title: "Back", style: UIBarButtonItemStyle.plain, target: self, action: Selector(("HomeTabController")))

self.navigationItem.leftBarButtonItem = backButton

上面的代码是在navigationController中创建按钮的，但是我可以创建一个无法编写要打开的特定视图控制器的按钮。

我尝试使用popViewController和popToRootViewController进行操作，需要特定的代码来借助特定的viewController故事板ID和快速打开特定的viewController viewcontrollername。

Answer 1

您需要在#selctor()（Swift 4版本）中添加功能名称

let backButton = UIBarButtonItem(title: "Back", style: .plain, target: self, action: #selector(goToViewController(_:)))

self.navigationItem.leftBarButtonItem = backButton

您需要创建一个功能。

@objc func goToViewController(_ sender: UIBarButtonItem) {

    //write code here to open a view controller

    let storyboard = "Main"
    let viewControllerIdentifier = "HomeVC"
    let viewController = UIStoryboard(name: storyboard, bundle: nil).instantiateViewController(withIdentifier: viewControllerIdentifier) as! HomeVC
    //push/present "viewController"
}

Answer 2

在此代码中，只需将ChatVC名称替换为您的视图控制器名称

@objc func goToViewController(_ sender: UIBarButtonItem) {
for controller in self.navigationController!.viewControllers as Array {
                if controller.isKind(of: ChatVC.self) {
                    self.navigationController!.popToViewController(controller, animated: true)
                    break
                } else {
                    self.navigationController?.popViewController(animated: true)
                }
            }
}

UIBARBUTTON后退动作

2 个答案: