Question

我正在尝试找出一种查询条件的语法，这似乎很常见。

下面的typedef以一对多对多（作者）关系存储代表作者的代理的ID值。我想在从Author模式获取详细信息的同时提取代理的名称。

type Author {
    id: ID!
    firstName: String
    middleInitial: String
    lastName: String
    posts: [Post]
    agent: ID

}

因此封闭的查询（返回所有作者的列表）如下所示：

{
  authors {
    firstName
    lastName
    agent
    }
}

这给了我座席的ID。我该如何使用相同的查询从类似于上面的typedef中获取代理的名称？

Answer 1

mysql> select * from wc_revenue;
+--------------+---------------+-------------+
| invoice_date | gross_revenue | net_revenue |
+--------------+---------------+-------------+
| 2018-06-28   |       1623.99 |      659.72 |
| 2018-06-27   |     112414.65 |    38108.13 |
| 2018-06-26   |       2518.74 |     1047.14 |
| 2018-06-25   |     475805.92 |   172193.58 |
| 2018-06-22   |       1151.79 |      478.96 |
| 2018-07-02   |        150.00 |      100.00 |
| 2018-07-05   |        350.00 |      250.00 |
| 2018-08-07   |        600.00 |      400.00 |
| 2018-08-09   |        900.00 |      600.00 |
+--------------+---------------+-------------+

mysql> SELECT month(invoice_date) as MTH, invoice_date, SUM(gross_revenue) AS gross_revenue, SUM(net_revenue) AS net_revenue 
FROM wc_revenue 
GROUP BY MTH, invoice_date WITH ROLLUP;
+------+--------------+---------------+-------------+
| MTH  | invoice_date | gross_revenue | net_revenue |
+------+--------------+---------------+-------------+
|    6 | 2018-06-22   |       1151.79 |      478.96 |
|    6 | 2018-06-25   |     475805.92 |   172193.58 |
|    6 | 2018-06-26   |       2518.74 |     1047.14 |
|    6 | 2018-06-27   |     112414.65 |    38108.13 |
|    6 | 2018-06-28   |       1623.99 |      659.72 |
|    6 | NULL         |     593515.09 |   212487.53 |
|    7 | 2018-07-02   |        150.00 |      100.00 |
|    7 | 2018-07-05   |        350.00 |      250.00 |
|    7 | NULL         |        500.00 |      350.00 |
|    8 | 2018-08-07   |        600.00 |      400.00 |
|    8 | 2018-08-09   |        900.00 |      600.00 |
|    8 | NULL         |       1500.00 |     1000.00 |
| NULL | NULL         |     595515.09 |   213837.53 |
+------+--------------+---------------+-------------+

Answer 2

查询看起来像这样。我不确定您的Agent typedef是什么样，但是您知道了

=IFERROR(IF(INDEX(D:D,AGGREGATE(14,6,ROW($D$1:D1)/(($B$1:B1 = B2)*($C$1:C1 = C2)),1))<D2,"Close","Open"),"Open")

如何实现graphQL子查询

2 个答案: