使用派生嵌套类的字符串列表将类对象序列化为C#Webapi中的XML

时间:2018-06-29 16:11:04

标签: c# xml asp.net-mvc asp.net-web-api

您好,我正在开发一个Web-API项目,该项目可以连接并使用多设备。我有一个要求,例如直接在移动打印设备(WizarPOS)中打印XML格式,我需要发送如下所示的响应格式。

<RESPONSE TYPE="PRINT" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<TERMINALID>993324</TERMINALID>
<LOCALDATETIME>2018-11-16 09:08:40</LOCALDATETIME>
<SERVERDATETIME>6/29/2018 3:33:34 PM</SERVERDATETIME>
<TXID>880034435</TXID>
<HOSTTXID>ID00008769249</HOSTTXID>
<AMOUNT>500</AMOUNT>
<CURRENCY>634</CURRENCY>
<LIMIT>0</LIMIT>
<RECEIPT>
    <LINES>14</LINES>
    <LINE>Provider Pin</LINE>
    <LINE>TerminalID:                                 993324</LINE>
    <LINE>Date:                                   29.06.2018</LINE>
    <LINE>TimeOfDay:                                15:06:SS</LINE>
    <LINE>Trace-No:                                   160537</LINE>
    <LINE>Receipt-No:                                 475514</LINE>
    <LINE>--------------------------------------------------</LINE>
    <LINE>Value:                                     500 QAR</LINE>
    <LINE>Product without VAT</LINE>
    <LINE>Service:                                7736737741</LINE>
    <LINE>Hotline:                               0110/400773</LINE>
    <LINE>Serial Number:                           778617719</LINE>
    <LINE>CashCode:</LINE>
    <LINE>2866-8195-3923-8894</LINE>
</RECEIPT>
<RESULT>0</RESULT>
<RESULTTEXT>Transaction Successful</RESULTTEXT>
<PINCREDENTIALS>
    <PIN>2846-4607-1987-3562</PIN>
    <SERIAL>778617719</SERIAL>
    <VALIDTO>11/29/2018 3:33:34 PM</VALIDTO>
</PINCREDENTIALS>

为此,我创建了两个主类和两个嵌套类,其中一个嵌套类具有字符串派生类列表,如下所示

[XmlRoot("RESPONSE", DataType = "PRINT")]
public class PinDirectResponseVM
{
    public int TERMINALID { get; set; }
    public string LOCALDATETIME { get; set; }
    public string SERVERDATETIME { get; set; }
    public int TXID { get; set; }
    public string HOSTTXID { get; set; }
    public string AMOUNT { get; set; }
    public string CURRENCY { get; set; }
    public string LIMIT { get; set; }
    [XmlArrayItem(ElementName = "LINE")]
    public ReceiptResponseVM RECEIPT { get; set; }
    public string RESULT { get; set; }
    public string RESULTTEXT { get; set; }
    public string AID { get; set; }
    public PinCredentialsResponseVM PINCREDENTIALS { get; set; }
}
public class ReceiptResponseVM : List<string>
{
    public int LINES { get; set; }
}
public class PinCredentialsResponseVM
{
    public string PIN { get; set; }
    public string SERIAL { get; set; }
    public string VALIDTO { get; set; }
}

当我返回'PinDirectResponseVM'对象时没有得到<LINES>14<LINES>标签时,我得到了这样的响应

<RESPONSE xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<TERMINALID>993324</TERMINALID>
<LOCALDATETIME>2018-11-16 09:08:40</LOCALDATETIME>
<SERVERDATETIME>6/29/2018 3:33:34 PM</SERVERDATETIME>
<TXID>880034435</TXID>
<HOSTTXID>ID00008769249</HOSTTXID>
<AMOUNT>500</AMOUNT>
<CURRENCY>634</CURRENCY>
<LIMIT>0</LIMIT>
<RECEIPT>
    <LINE>Provider Pin</LINE>
    <LINE>TerminalID:                                 993324</LINE>
    <LINE>Date:                                   29.06.2018</LINE>
    <LINE>TimeOfDay:                                15:06:SS</LINE>
    <LINE>Trace-No:                                   160537</LINE>
    <LINE>Receipt-No:                                 475514</LINE>
    <LINE>--------------------------------------------------</LINE>
    <LINE>Value:                                     500 QAR</LINE>
    <LINE>Product without VAT</LINE>
    <LINE>Service:                                7736737741</LINE>
    <LINE>Hotline:                               0110/400773</LINE>
    <LINE>Serial Number:                           778617719</LINE>
    <LINE>CashCode:</LINE>
    <LINE>2866-8195-3923-8894</LINE>
</RECEIPT>
<RESULT>0</RESULT>
<RESULTTEXT>Transaction Successful</RESULTTEXT>
<PINCREDENTIALS>
    <PIN>2846-4607-1987-3562</PIN>
    <SERIAL>778617719</SERIAL>
    <VALIDTO>11/29/2018 3:33:34 PM</VALIDTO>
</PINCREDENTIALS>

因此,请根据我的要求帮助我获得响应,为此生成XML的最佳方法是什么?

1 个答案:

答案 0 :(得分:1)

这是因为<RECEIPT></RECEIPT>节点中有两个不同的子节点

<LINES></LINES>
<LINE></LINE>

您可以执行以下操作:

    XmlRoot("RESPONSE", DataType = "PRINT")]
    public class PinDirectResponseVM
    {
        public int TERMINALID { get; set; }
        public string LOCALDATETIME { get; set; }
        public string SERVERDATETIME { get; set; }
        public int TXID { get; set; }
        public string HOSTTXID { get; set; }
        public string AMOUNT { get; set; }
        public string CURRENCY { get; set; }
        public string LIMIT { get; set; }

        public ReceiptResponseVM RECEIPT { get; set; }
        public string RESULT { get; set; }
        public string RESULTTEXT { get; set; }
        public string AID { get; set; }
        public PinCredentialsResponseVM PINCREDENTIALS { get; set; }
    }
    public class ReceiptResponseVM //: List<string>
    { 
        [XmlElement(Order = 1, ElementName = "LINES")]
        public int LINES { get; set; }

        [XmlElement(Order = 2, ElementName = "LINE")]
        public List<string> LINE {get; set;}
    }
    public class PinCredentialsResponseVM
    {
        public string PIN { get; set; }
        public string SERIAL { get; set; }
        public string VALIDTO { get; set; }

}