无法使用发帖请求转到下一页

时间:2018-06-29 11:00:44

标签: python python-3.x web-scraping beautifulsoup

我用python编写了一个脚本,以从网页中获取指向不同文章的不同链接。运行脚本后,我可以完美地获取它们。但是,我面临的问题是文章链接遍历多个页面,因为它们的数量很大,可以容纳在单个页面中。如果我单击下一页按钮,则可以在开发人员工具中看到的附件信息实际上是通过发布请求产生ajax调用的。由于没有链接到该下一页按钮,因此我找不到任何方法可以转到下一页并从那里解析链接。我已经尝试过将post requestformdata一起使用,但是它似乎不起作用。我要去哪里错了?

Link to the landing page containing articles

这是我在单击下一页按钮时使用chrome开发工具所获得的信息:

GENERAL
=======================================================
Request URL: https://www.ncbi.nlm.nih.gov/pubmed/
Request Method: POST
Status Code: 200 OK
Remote Address: 130.14.29.110:443
Referrer Policy: origin-when-cross-origin

RESPONSE HEADERS
=======================================================
Cache-Control: private
Connection: Keep-Alive
Content-Encoding: gzip
Content-Security-Policy: upgrade-insecure-requests
Content-Type: text/html; charset=UTF-8
Date: Fri, 29 Jun 2018 10:27:42 GMT
Keep-Alive: timeout=1, max=9
NCBI-PHID: 396E3400B36089610000000000C6005E.m_12.03.m_8
NCBI-SID: CE8C479DB3510951_0083SID
Referrer-Policy: origin-when-cross-origin
Server: Apache
Set-Cookie: ncbi_sid=CE8C479DB3510951_0083SID; domain=.nih.gov; path=/; expires=Sat, 29 Jun 2019 10:27:42 GMT
Set-Cookie: WebEnv=1Jqk9ZOlyZSMGjHikFxNDsJ_ObuK0OxHkidgMrx8vWy2g9zqu8wopb8_D9qXGsLJQ9mdylAaDMA_T-tvHJ40Sq_FODOo33__T-tAH%40CE8C479DB3510951_0083SID; domain=.nlm.nih.gov; path=/; expires=Fri, 29 Jun 2018 18:27:42 GMT
Strict-Transport-Security: max-age=31536000; includeSubDomains; preload
Transfer-Encoding: chunked
Vary: Accept-Encoding
X-UA-Compatible: IE=Edge
X-XSS-Protection: 1; mode=block

REQUEST HEADERS
========================================================
Accept: text/html, */*; q=0.01
Accept-Encoding: gzip, deflate, br
Accept-Language: en-US,en;q=0.9
Connection: keep-alive
Content-Length: 395
Content-Type: application/x-www-form-urlencoded; charset=UTF-8
Cookie: ncbi_sid=CE8C479DB3510951_0083SID; _ga=GA1.2.1222765292.1530204312; _gid=GA1.2.739858891.1530204312; _gat=1; WebEnv=18Kcapkr72VVldfGaODQIbB2bzuU50uUwU7wrUi-x-bNDgwH73vW0M9dVXA_JOyukBSscTE8Qmd1BmLAi2nDUz7DRBZpKj1wuA_QB%40CE8C479DB3510951_0083SID; starnext=MYGwlsDWB2CmAeAXAXAbgA4CdYDcDOsAhpsABZoCu0IA9oQCZxLJA===
Host: www.ncbi.nlm.nih.gov
NCBI-PHID: 396E3400B36089610000000000C6005E.m_12.03
Origin: https://www.ncbi.nlm.nih.gov
Referer: https://www.ncbi.nlm.nih.gov/pubmed
User-Agent: Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36
X-Requested-With: XMLHttpRequest

FORM DATA
========================================================
p$l: AjaxServer
portlets: id=relevancesortad:sort=;id=timelinead:blobid=NCID_1_120519284_130.14.22.215_9001_1530267709_1070655576_0MetA0_S_MegaStore_F_1:yr=:term=%222015%22%5BDate%20-%20Publication%5D%20%3A%20%223000%22%5BDate%20-%20Publication%5D;id=reldata:db=pubmed:querykey=1;id=searchdetails;id=recentactivity
load: yes

到目前为止,这是我的脚本(如果没有注释,则get请求可以完美地工作,但对于第一页而言):

import requests
from urllib.parse import urljoin
from bs4 import BeautifulSoup

geturl = "https://www.ncbi.nlm.nih.gov/pubmed/?term=%222015%22%5BDate+-+Publication%5D+%3A+%223000%22%5BDate+-+Publication%5D"
posturl = "https://www.ncbi.nlm.nih.gov/pubmed/"

# res = requests.get(geturl,headers={"User-Agent":"Mozilla/5.0"})
# soup = BeautifulSoup(res.text,"lxml")
# for items in soup.select("div.rslt p.title a"):
#     print(items.get("href"))

FormData={
    'p$l': 'AjaxServer',
    'portlets': 'id=relevancesortad:sort=;id=timelinead:blobid=NCID_1_120519284_130.14.22.215_9001_1530267709_1070655576_0MetA0_S_MegaStore_F_1:yr=:term=%222015%22%5BDate%20-%20Publication%5D%20%3A%20%223000%22%5BDate%20-%20Publication%5D;id=reldata:db=pubmed:querykey=1;id=searchdetails;id=recentactivity',
    'load': 'yes'
    }

req = requests.post(posturl,data=FormData,headers={"User-Agent":"Mozilla/5.0"})
soup = BeautifulSoup(req.text,"lxml")
for items in soup.select("div.rslt p.title a"):
    print(items.get("href"))

顺便说一句,当我单击下一页链接时,浏览器中的URL变为“ https://www.ncbi.nlm.nih.gov/pubmed”。

我不想寻求与任何浏览器模拟器相关的任何解决方案。预先感谢。

2 个答案:

答案 0 :(得分:2)

内容是高度动态的,因此最好使用selenium或类似的客户端,但是我意识到,由于结果数量如此之多,因此这是不切实际的。因此,我们必须分析浏览器提交的HTTP请求,并使用requests模拟它们。

下一页的内容由POST请求加载到/pubmed,并且发布数据是EntrezForm表单的输入字段。表单提交由js控制(单击“下一页”按钮时触发),并使用.submit()方法执行。

经过一番检查,我发现了一些有趣的领域:

  • EntrezSystem2.PEntrez.PubMed.Pubmed_ResultsPanel.Pubmed_Pager.CurrPage
    EntrezSystem2.PEntrez.PubMed.Pubmed_ResultsPanel.Pubmed_Pager.cPage指示当前页面和下一页。

  • EntrezSystem2.PEntrez.DbConnector.Cmd似乎正在执行数据库查询。如果我们不提交此字段,结果将不会更改。

  • EntrezSystem2.PEntrez.PubMed.Pubmed_ResultsPanel.Pubmed_DisplayBar.PageSizeEntrezSystem2.PEntrez.PubMed.Pubmed_ResultsPanel.Pubmed_DisplayBar.PrevPageSize表示每页结果数。

有了这些信息,我可以使用以下脚本获取多个页面。

import requests
from urllib.parse import urljoin
from bs4 import BeautifulSoup

geturl = "https://www.ncbi.nlm.nih.gov/pubmed/?term=%222015%22%5BDate+-+Publication%5D+%3A+%223000%22%5BDate+-+Publication%5D"
posturl = "https://www.ncbi.nlm.nih.gov/pubmed/"

s = requests.session()
s.headers["User-Agent"] = "Mozilla/5.0"

soup = BeautifulSoup(s.get(geturl).text,"lxml")
inputs = {i['name']: i.get('value', '') for i in soup.select('form#EntrezForm input[name]')}

results = int(inputs['EntrezSystem2.PEntrez.PubMed.Pubmed_ResultsPanel.Pubmed_ResultsController.ResultCount'])
items_per_page = 100
pages = results // items_per_page + int(bool(results % items_per_page))

inputs['EntrezSystem2.PEntrez.PubMed.Pubmed_ResultsPanel.Pubmed_DisplayBar.PageSize'] = items_per_page
inputs['EntrezSystem2.PEntrez.PubMed.Pubmed_ResultsPanel.Pubmed_DisplayBar.PrevPageSize'] = items_per_page
inputs['EntrezSystem2.PEntrez.DbConnector.Cmd'] = 'PageChanged'

links = []

for page in range(pages):
    inputs['EntrezSystem2.PEntrez.PubMed.Pubmed_ResultsPanel.Pubmed_Pager.CurrPage'] = page + 1
    inputs['EntrezSystem2.PEntrez.PubMed.Pubmed_ResultsPanel.Pubmed_Pager.cPage'] = page

    res = s.post(posturl, inputs)
    soup = BeautifulSoup(res.text, "lxml")

    items = [i['href'] for i in soup.select("div.rslt p.title a[href]")]
    links += items

    for i in items:
        print(i)

我要求每页100个项目,因为更高的数字似乎“破坏了”服务器,但是您应该能够通过一些错误检查来调整该数字。

最后,链接以降序显示(/29960282/29960281,...),所以我认为我们可以在不执行任何POST请求的情况下计算链接:

geturl = "https://www.ncbi.nlm.nih.gov/pubmed/?term=%222015%22%5BDate+-+Publication%5D+%3A+%223000%22%5BDate+-+Publication%5D"
posturl = "https://www.ncbi.nlm.nih.gov/pubmed/"

s = requests.session()
s.headers["User-Agent"] = "Mozilla/5.0"
soup = BeautifulSoup(s.get(geturl).text,"lxml")

results = int(soup.select_one('[name$=ResultCount]')['value'])
first_link = int(soup.select_one("div.rslt p.title a[href]")['href'].split('/')[-1])
last_link = first_link - results

links = [posturl + str(i) for i in range(first_link, last_link, -1)]

但不幸的是,结果不准确。

答案 1 :(得分:0)

不要将此问题视为XY问题,因为如果解决了,它应该会提供一个非常有趣的解决方案,但我发现针对此 specific 问题的解决方案效率更高: {3}}和方便的NCBI's Entrez Programming Utilities

使用我entrez.py中的Entrez存储库中的PATH脚本,我创建了这个脚本,该脚本可以根据需要打印出链接:

from entrez import on_search
import re

db = 'pubmed'
term = '"2015"[Date - Publication] : "3000"[Date - Publication]'
link_base = f'https://www.ncbi.nlm.nih.gov/{db}/'

def links_generator(db, term):
    for line in on_search(db=db, term=term, tool='link'):
        match = re.search(r'<Id>([0-9]+)</Id>', line)
        if match: yield (link_base + match.group(1))

for link in links_generator(db, term):
    print(link)

输出:

https://www.ncbi.nlm.nih.gov/pubmed/29980165
https://www.ncbi.nlm.nih.gov/pubmed/29980164
https://www.ncbi.nlm.nih.gov/pubmed/29980163
https://www.ncbi.nlm.nih.gov/pubmed/29980162
https://www.ncbi.nlm.nih.gov/pubmed/29980161
https://www.ncbi.nlm.nih.gov/pubmed/29980160
https://www.ncbi.nlm.nih.gov/pubmed/29980159
https://www.ncbi.nlm.nih.gov/pubmed/29980158
https://www.ncbi.nlm.nih.gov/pubmed/29980157
https://www.ncbi.nlm.nih.gov/pubmed/29980156
https://www.ncbi.nlm.nih.gov/pubmed/29980155
https://www.ncbi.nlm.nih.gov/pubmed/29980154
https://www.ncbi.nlm.nih.gov/pubmed/29980153
https://www.ncbi.nlm.nih.gov/pubmed/29980152
https://www.ncbi.nlm.nih.gov/pubmed/29980151
https://www.ncbi.nlm.nih.gov/pubmed/29980150
https://www.ncbi.nlm.nih.gov/pubmed/29980149
https://www.ncbi.nlm.nih.gov/pubmed/29980148
...

opensource, unofficial Entrez repo相比,它们的顺序相同。 :-)