我有一些子查询,需要返回不同的结果。每个子查询使用不同的聚合函数,例如SUM()
和COUNT(*)
。我所做的是用SELECT (SELECT subquery, SELECT subquery)
封装它们,不确定是否可行。
预期结果:
TwoYears
123
5
SELECT(
(SELECT
(SELECT SUM(AHT)
FROM
(
SELECT
CASE
WHEN DATEDIFF(year, [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[HireDate], GETDATE()) >= 2 AND (DATEDIFF(year, [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[HireDate], GETDATE())) <= 2 OR (DATEDIFF(year, [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[HireDate], GETDATE())) <= 1
THEN [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[Value]
END AS AHT
FROM [AgentProfile_CRT].[dbo].[uvw_AHTMaster] WHERE [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[Month] = 'January' AND [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[Year] = 2018 AND [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[AccountID] = 8 AND [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[LOBID] = 23
) f
WHERE AHT = AHT ) AS TwoYears),
(SELECT
(SELECT COUNT(*) AS TwoYears
FROM
(
SELECT
CASE
WHEN DATEDIFF(year, [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[HireDate], GETDATE()) >= 2 AND (DATEDIFF(year, [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[HireDate], GETDATE())) <= 2 OR (DATEDIFF(year, [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[HireDate], GETDATE())) <= 1
THEN 'Good'
END AS Result
FROM [AgentProfile_CRT].[dbo].[uvw_AHTMaster] WHERE [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[Month] = 'January' AND [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[Year] = 2018 AND [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[AccountID] = 8 AND [AgentProfile_CRT].[dbo].[uvw_AHTMaster].[LOBID] = 23
) f
WHERE Result = 'Good') AS TwoYears)
) a
答案 0 :(得分:1)
您需要全部合并并删除一些子选择。
赞:
7bit