Question

我正在研究Python中的多处理，并试图创建2个进程并通过Pipe在它们之间交换数据。

在下面的代码中，我期望sender每秒向receiver发送一个随机整数，然后receiver将该值写入文件multi.txt。

但是即使运行代码后文件也为空。该代码的问题是什么？我是否在某处误解了某些东西或犯了错误？

import multiprocessing as mp
import time
import random
import os

pipe1, pipe2 = mp.Pipe()  


class sender(mp.Process):
    def __init__(self):
        mp.Process.__init__(self)

    def run(self):
        print('SENDER PID: ', os.getpid() )
        while True:
            value = random.randint(0, 10)
            pipe1.send(value)
            #print(pipe2.recv())    # <--- prints out value without problems
            time.sleep(1)


class receiver(mp.Process):
    def __init__(self):
        mp.Process.__init__(self)

    def run(self):
        print('RECEIVER PID: ', os.getpid() )
        while True:
            #print(pipe2.recv())     # <--- doesn't print out value or write it to file
            os.chdir('C:\\Users\\J\\Desktop\\NEW_TRO')
            file = open("multi.txt", "a")
            file.write(pipe2.recv())
            file.close()



if __name__ == '__main__':
    print('MAIN PID: ', os.getpid() )

    p1 = sender()
    p2 = receiver()
    p1.start()
    p2.start()

#mp.freeze_support()

如何在Python中通过Pipe交换数据？

0 个答案: