Question

我将如何遍历SMLNJ中的列表。我已经在这里待了三个小时了，我一生都无法解决。

因此，仅遍历并打印列表即可。用最简单的方法[5,2,3]可以打印出5 2 3或此列表的变体。

Answer 1

我将如何遍历SMLNJ中的列表

这取决于您要执行的遍历类型：映射，折叠，迭代。

使用递归：

(* mapping: *)
fun incr_each_by_1 [] = []
  | incr_each_by_1 (x::xs) = x + 1 :: incr_each_by_1 xs

val demo_1 = incr_each_by_1 [5,2,3] (* [6,3,4] *)

(* folding: *)
fun sum_all_together [] = 0
  | sum_all_together (x::xs) = x + sum_all_together xs

val demo_2 = sum [5,2,3] (* 10 *)

(* iteration: *)
fun print_each [] = ()
  | print_each (x::xs) = ( print (Int.toString x ^ "\n") ; print_each xs )

val demo_3 = print_each [5,2,3] (* no result, but side-effect *)

使用高阶函数：

val demo_1 = List.map (fn x => x + 1) [5,2,3]
val demo_2 = List.foldl (fn (x, result) => x + result) 0 [5,2,3]
val demo_3 = List.app (fn x => Int.toString x ^ "\n") [5,2,3]

SMLNJ列表遍历

1 个答案: