我在python下面定义了一个函数,用于根据已经检索到的business_id提取运行时间:
def hours_operation(business_id):
day = day_open(business_id)
start = day_start(business_id)
end = day_end(business_id)
day1 = []
for i in day:
try:
value = "start"+str(i)
except:
value = 'None'
day1.append(value)
dict1 = {}
for i in range(len(day1)):
dict1[day1[i]]=start[i]
start_df = pd.DataFrame(dict1, index=[0])
day2 = []
for i in day:
day2.append("end"+str(i))
dict2 = {}
for i in range(len(day2)):
dict2[day2[i]]=end[i]
end_df = pd.DataFrame(dict2, index=[0])
for i in day:
start_df['end'+str(i)]=end_df['end'+str(i)]
return start_df
问题是我的输出显示如下:
Out[36]:
start0 start1 start2 start3 start4 ... end2 end3 end4 end5 end6
0 1100 1100 1100 1100 1100 ... 2200 2200 2200 2200 2100
但是,如果企业每周仅工作4天而不是7天,我喜欢这种格式。我希望它以N / A的形式返回开始和结束。
如果一家公司仅工作4天,这就是我期望的输出:
start0 start1 start2 start3 start4 start5 start6 end1 end2 end3 end4 end5 end6
0 1100 1100 1100 1100 1100 N/A N/A 2200 2200 2200 N/a N/A
答案 0 :(得分:0)
您可以使用python第三级条件语句,如下所示:
version: "3.2"
services:
superservice:
image: docker
command: docker run -it --restart unless-stopped --device=/dev/video0 --volume=/path:/path --name container_name my/image
volumes:
- /var/run/docker.sock:/var/run/docker.sock
deploy:
replicas: 1
mode: replicated
restart_policy:
condition: unless-stopped
resources:
limits:
cpus: '0.70'
memory: 50M
reservations:
cpus: '0.25'
memory: 20M
placement:
constraints: [node.role == manager]
stdin_open: true
tty: true
这假设dict1[day1[i]]= start[i] if start[i] is not None else 'N/a'
是开始时间的值,并且您不想输出的值是NoneType对象。例如,如果它是0或某个字符串,则只需更新该语句中的条件即可反映出来。 (当然,结束时间您将不得不做同样的事情)