Question

我正在尝试使用react-native-sqlite-storage将数据保留在设备上。

但是我需要在代码中使用大量事务，并且当我尝试通过SQLite.openConnection返回实例并打开事务不起作用时。而且，如果我尝试从我的数据库实例执行executeSql，那么它会完美地工作。

db，如果我的实例来自SQLite.openConnection()

// THIS WORKS
db.executeSql(queryCreateTable)
  .catch(erro => console.log(`erro executesql ${erro}`));

db.executeSql('INSERT INTO PEOPLE VALUES ("Mateus Pereira", 20)')
  .catch(erro => console.log(`erro executesql ${erro}`));

db.executeSql('SELECT * FROM PEOPLE').then(([results]) => {
  const { rows } = results;
  console.log(rows);
  for (let i = 0; i < rows.length; i += 1) {
    const row = rows.item(i);
    console.log(`Name: ${row.nome}, Idade: ${row.idade}`);
  }
});

// THIS DOESNT WORK
db.transaction().then((tx) => {
  tx.executeSql(queryCreateTable)
    .catch(erro => console.log(`erro executesql ${erro}`));

  tx.executeSql('INSERT INTO PEOPLE VALUES ("Mateus Pereira", 20)')
    .catch(erro => console.log(`erro executesql ${erro}`));

  tx.executeSql('SELECT * FROM PEOPLE').then(([results]) => {
    const { rows } = results;
    console.log(rows);
    for (let i = 0; i < rows.length; i += 1) {
      const row = rows.item(i);
      console.log(`Name: ${row.nome}, Idade: ${row.idade}`);
    }
  });
}).catch(error => console.log(error));


{
    "db": {
        "openargs": {
            "name": "Test2.db",
            "dblocation": "nosync"
        },
        "dbname": "Test2.db"
    },
    "txlock": true,
    "readOnly": false,
    "executes": []
}

Answer 1

以下是使用交易的方法：

db.transaction(tx => {
  tx.executeSql(`SELECT ...`)
  .then([tx2, results]) => {

  }
  .catch((error) => {
    console.log(error);
  });
});

尝试打开事务时

1 个答案: