Question

如何在MySQL中执行以下操作- 我有一个包含客户订单的数据库，我只想显示两种类型的订单的客户记录，而只显示这两种类型的订单。

示例-

  Orders:
    'Customer Id'   'Product'
    0001            Widget 1
    0001            Widget 2
    0001            Widget 3
    0002            Widget 2
    0002            Widget 3
    0003            Widget 1
    0004            Widget 1
    0004            Widget 3
    0004            Widget 4
    0004            Widget 5

我只想显示已订购小部件1和小部件3的客户，并且仅显示那些订单

所需结果-

  Orders:
    'Customer Id'   'Product'
    0001            Widget 1
    0001            Widget 3
    0004            Widget 1
    0004            Widget 3

Answer 1

尝试将订单与窗口小部件列表一起加入，同时强制组中的行数与列表中的行数相同。

SELECT
    X.*
FROM
    Orders X
    INNER JOIN (
        SELECT
            O.`Customer Id`
        FROM
            Orders O
            LEFT JOIN (
                SELECT 'Widget 1' Product
                UNION ALL
                SELECT 'Widget 3' Product
            ) P ON O.Product = P.Product
        GROUP BY
            O.`Customer Id`
        HAVING
            COUNT(P.product) = COUNT(1)
    ) M ON X.`Customer Id` = M.`Customer Id`

Answer 2

SELECT *
FROM ORDERS O1, ORDERS O2
WHERE O1.customer_id = O2.customer_id
AND ( O1.Product = "Widget 1"
AND  O2.Product = "Widget 3" )
OR (O1.Product = "Widget 3"
AND  O2.Product = "Widget 1")
AND O1.customer_id NOT IN (
       SELECT customer_id
       FROM ORDERS O3, ORDERS O4
       WHERE O3.customer_id = O4.customer_id
       AND (O3.Product <> "Widget 1"
       OR O4.Product <> "Widget 3")
       OR (O3.Product <> "Widget 3"
       OR O4.Product <> "Widget 1")
)

请将“客户ID”更改为“ customer_id”，列名中的空格不是一个好主意

Answer 3

我将使用聚合：

select o.customer_id
from orders o
group by o.customer_id
having sum( (product = 'Widget 1') ) > 0 and
       sum( (product = 'Widget 3') ) > 0 and
       sum( (product not in ('Widget 1', 'Widget 3')) );

我认为没有理由自行退回产品，但如果您确实需要，可以添加group_concat(product)。

如果要原始行，可以使用以上内容进行过滤。或者：

select o.*
from orders o
where o.product in ('Widget 1', 'Widget 3') and
      not exists (select 1
                  from orders o2
                  where o2.customer_id = o.customer_id and
                        o2.product not in ('Widget 1', 'Widget 3')
                 );

Answer 4

如何？

SELECT custid, product FROM transactions WHERE custid IN 
(SELECT custid
FROM transactions
WHERE product in ('w1', 'w3')
GROUP BY custid
HAVING COUNT(DISTINCT product) = 2) 
and product IN('w1', 'w3');

仅显示同时具有记录类型和那些记录的客户

4 个答案: