Question

我在这里尝试了另一篇关于标题样式未应用的文章，但是该代码也没有执行任何操作。在这里，我的PHPWord构建了使用“ Open Sans”成功显示硬编码变量的部分。但是当我更改为在表中显示信息时，它始终默认为“ Arial” 10。请查看是否可以帮助您说明为什么会发生这种情况，谢谢！注意-为了使输出在单元格之间均匀显示行，我正在尝试文本中的其他样式。即使我将$ BodyFontStyle应用于每个addCell，addText和addRow，仍然-仅Arial。我需要将该表格显示在“无休假” 10中。请帮助-

$firstRowStyle = array('name' => 'Open Sans', 'size' => 10, 'valign' => 'bottom');
$BodyFontStyle = array('name'=>'Open Sans', 'bold'=>false, 'size'=>14);
$table_cell_style = array('valign' => 'top');
$lineStyle = array('name' => 'Open Sans', 'size' => 10, 'valign' => 'bottom');

//from above, this flag is not set, or set:
if ($signatory_found == 1) { //from mySQL query looking for Signatory.

    $PHPWord->addTableStyle('BodyFontStyle', array('name'=>'Open Sans', 'bold'=>false, 'size'=>14));
    $table = $section->addTable('BodyFontStyle');

    //tried this, to no avail:
    //$PHPWord->addTableStyle($BodyFontStyle);
    //$table = $section->addTable($BodyFontStyle);

    for ($i=0; $i <= $counter; $i++) {
        $table->addRow();
        $table->addCell(1600, $firstRowStyle)->addText("BY:_____________________________________________________");
        $table->addCell(200, $firstRowStyle)->addText('');
        $table->addCell(1600, $firstRowStyle)->addText("     ____________________________");
        $table->addRow();

        $full_name_title = "    " . $signatory_results[$i]['first'] . " " . $signatory_results[$i]['last'] . ", " . $signatory_results[$i]['title'];

        $table->addCell(1600, $table_cell_style)->addText("{$full_name_title}");
        $table->addCell(200, $firstRowStyle)->addText(''); //space between name, and date.
        $table->addCell(1600, $table_cell_style)->addText("                          Date");
    }
} else { //else signatory flag was not set to 1, so no records found.

    $table = $section->addTable('BodyFontStyle');
    $PHPWord->addTableStyle('BodyFontStyle', array('name'=>'Open Sans', 'bold'=>false, 'size'=>14));

    $table->addRow();
    $table->addCell(1600, $firstRowStyle)->addText("BY:_________________________________");
    $table->addCell(200, $firstRowStyle)->addText('');
    $table->addCell(1600, $firstRowStyle)->addText("_______________________");

    $table->addRow();
    $table->addCell(1600, $firstRowStyle)->addText("          Signature");
    $table->addCell(200, $firstRowStyle)->addText('');
    $table->addCell(1600, $firstRowStyle)->addText("                Date");

    $table->addRow();
    $table->addCell(1600, $lineStyle)->addText("     ____________________________________", array(), array('cellMarginLeft' => 6));
    $table->addCell(200, $firstRowStyle)->addText('');
    $table->addCell(1600, $firstRowStyle)->addText("_______________________");

    $table->addRow();
    $table->addCell(1600, $table_cell_style)->addText("          Print Name");
    $table->addCell(200, $firstRowStyle)->addText('');
    $table->addCell(1600, $table_cell_style)->addText("                Print Title");
}

// Hack - Martin/Pitt has a / in the LP Short name which messes up the filename/path
$LPShort = str_replace("/", "-", $LPShort);
$LPShort = str_replace(" ", "-", $LPShort);

$objWriter = \PhpOffice\PhpWord\IOFactory::createWriter( $PHPWord, 'Word2007' );
$filelocation = '/var/www/company/contracts/tmp';
$filename = 'Sig_'.$LPShort."_".date('YmdHis',time()).'.docx';
$FullName = $filelocation.'/'.$filename;
//echo $FullName;
$objWriter->save($FullName);

echo $filename;
exit;

Answer 1

修复-我不会再次发布所有代码，但是此命令将显示解决方案。关键是在文本之后的末尾，使定义的样式与addCell命令内联。注意，上面，我只是带有文本的addCell，但后面没有样式。我将在命令之前和之后进行解释：

/*BEFORE* $table->addCell(1600, $table_cell_style)->addText("{$full_name_title}");

/*AFTER*/ $table->addCell(1600, $table_cell_style)->addText("{$full_name_title}", $BodyFontStyle);

PHPWord-表样式始终默认为Arial 10，不应用新样式

1 个答案: