我正在尝试运行此查询:
UPDATE anothertable
INNER JOIN (SELECT *,
LEAST(table1.from_price, table2.from_price, table3.from_price) AS cheapestPrice
FROM (SELECT * FROM table1 v WHERE hotelid >= 1
UNION
SELECT * FROM table2 c WHERE hotelid >= 1
UNION
SELECT * FROM table3 k WHERE hotelid >= 1) AS temp
GROUP BY temp.hotelid, temp.country) AS i ON anothertable.id = i.hotelid
AND anothertable.country = i.country
SET price = i.cheapestPrice,
op = i.to
但是我无法获得LEAST
函数来访问名为“from_price”的字段。
想法?
答案 0 :(得分:2)
你应该使用Min而不是Least:
Update anothertable
Join (
Select hotelid, country, to
, Min(from_price) AS cheapestPrice
From (
Select hotelid, country, from_price, to
From table1 v
Where hotelid >= 1
Union
Select hotelid, country, from_price, to
From table2 c
Where hotelid >= 1
Union
Select hotelid, country, from_price, to
From table3 k
Where hotelid >= 1
) AS temp
Group By temp.hotelid, temp.country, temp.to
) As i
On anothertable.id = i.hotelid
And anothertable.country = i.country
Set price = i.cheapestPrice
, op = i.to
修改强>
正如评论中所指出的,我从内部临时查询中省略了to
列。但是,我发现不清楚应该如何包含to
因为你在声明Group By列方面使用了MySQL的一个可怕特性。我假设你需要在组中包含to
但是如果不是这种情况,你应该明确它应该在to
列上使用哪个聚合函数。
这是我在to
列上使用Min的替代方案:
Update anothertable
Join (
Select temp.hotelid, temp.country
, Min(temp.to) As to
, Min(temp.from_price) AS cheapestPrice
From (
Select v.hotelid, v.country, v.from_price, v.to
From table1 v
Where hotelid >= 1
Union
Select c.hotelid, c.country, c.from_price, c.to
From table2 c
Where hotelid >= 1
Union
Select k.hotelid, k.country, k.from_price, k.to
From table3 k
Where hotelid >= 1
) AS temp
Group By temp.hotelid, temp.country
) As i
On anothertable.id = i.hotelid
And anothertable.country = i.country
Set price = i.cheapestPrice
, op = i.to