我有一个包含 employeeProjectId 的对象数组，它们可能是相同的。因此，我要寻找的是，如果有多个相同的employeeProjectId，则将结果合并为具有数组形式的 projectRoles 的一个对象。 下面给出响应以供参考。 谢谢：）
{
"code": 200,
"success": true,
"message": "Successfully completed",
"data": [
{
"employeeProjectId": 1,
"projectRoleId": 1,
"employee_project": {
"id": 1,
"status": true,
"type": "backup",
"startDate": "2018-06-28T07:20:36.000Z",
"endDate": "2018-06-29T07:20:39.000Z",
"allocation": 100,
"employeeId": 326,
"projectId": 35,
"employee": {
"firstName": "Asad",
"lastName": "Marfani"
},
"project": {
"name": "RTA"
}
},
"project_role": {
"id": 1,
"role": "front_end_ios"
}
},
{
"employeeProjectId": 1,
"projectRoleId": 2,
"employee_project": {
"id": 1,
"status": true,
"type": "backup",
"startDate": "2018-06-28T07:20:36.000Z",
"endDate": "2018-06-29T07:20:39.000Z",
"allocation": 100,
"employeeId": 326,
"projectId": 35,
"employee": {
"firstName": "Asad",
"lastName": "Marfani"
},
"project": {
"name": "RTA"
}
},
"project_role": {
"id": 2,
"role": "Front End - Android"
}
},
{
"employeeProjectId": 3,
"projectRoleId": 1,
"employee_project": {
"id": 3,
"status": true,
"type": "backup",
"startDate": "2018-06-28T07:47:19.000Z",
"endDate": "2018-06-29T07:47:22.000Z",
"allocation": 50,
"employeeId": 16,
"projectId": 35,
"employee": {
"firstName": "Nosheen",
"lastName": "Sikandar"
},
"project": {
"name": "RTA"
}
},
"project_role": {
"id": 1,
"role": "front_end_ios"
}
},
{
"employeeProjectId": 3,
"projectRoleId": 3,
"employee_project": {
"id": 3,
"status": true,
"type": "backup",
"startDate": "2018-06-28T07:47:19.000Z",
"endDate": "2018-06-29T07:47:22.000Z",
"allocation": 50,
"employeeId": 16,
"projectId": 35,
"employee": {
"firstName": "Nosheen",
"lastName": "Sikandar"
},
"project": {
"name": "RTA"
}
},
"project_role": {
"id": 3,
"role": "Front End - Web"
}
}
]}
我想要这样：
{
"code": 200,
"success": true,
"message": "Successfully completed",
"data": [
{
"employeeProjectId": 1,
"employee_project": {
"id": 1,
"status": true,
"type": "backup",
"startDate": "2018-06-28T07:20:36.000Z",
"endDate": "2018-06-29T07:20:39.000Z",
"allocation": 100,
"employeeId": 326,
"projectId": 35,
"employee": {
"firstName": "Asad",
"lastName": "Marfani"
},
"project": {
"name": "RTA"
}
},
"project_role": [
{
"id": 1,
"role": "front_end_ios",
},
{
"id": 2,
"role": "front_end_web"
}
]
}
]}
答案 0 :(得分：1)
您可以使用map创建一个组数组（employeeProjectIds），并使用该数组将其简化为组。
我觉得employee_project中的字段也需要合并，因为开始，结束日期和分配对于员工和项目都是唯一的。
然后映射合并数据中的组数组：
const data = [{"employeeProjectId":1,"project_role":"a"},{"employeeProjectId":1,"project_role":"b"},{"employeeProjectId":3,"project_role":"a"},{"employeeProjectId":3,"project_role":"c"}];
const groupBy = (getGroup,array) => {
//use getGroup function to get the group identifyer of the items (is employeeProjectId)
const groups = array.map(getGroup);
return array.reduce(//reduce array into array of arrays that are grouped
(result,item,index)=>{
//get the group of current item
const itemGroup = getGroup(item);
//find the index of this item in groups
const indexOfGroup = groups.indexOf(itemGroup);
//index of this item in groups is current index so it's first item of the group
if(indexOfGroup===index){
return result.concat([[item]])
}
//it is not first item of the group, add this item to it's correct group
//add current item to the right group
result.find(([item])=>getGroup(item)===itemGroup).push(item);
return result;
},
[]//initial result
)
}
const merge = (item1,item2) => {
//if project_role is not an array yet, make it an array
if(!Array.isArray(item1.project_role)){
item1 = {...item1,project_role:[item1.project_role]};
}
//add project_role of item2 to item1
item1.project_role.push(item2.project_role);
return item1;
};
const grouped = groupBy(x=>x.employeeProjectId,data);
console.log("grouped",grouped);
console.log(
"grouped and merged",
groupBy(x=>x.employeeProjectId,data).map(
group=>
group.reduce(merge)
)
)
您可能不熟悉某些语法，例如spread in object literals来复制对象（不是深层副本），arrow functions和destructuring assignment试图在对象中查找元素时使用的语法数组。
map和reduce方法已记录在here
中答案 1 :(得分：0)
我想您正在寻找类似这样的东西：D
否则，您也可以使用lodash模块。
const obj = {
"code": 200,
"success": true,
"message": "Successfully completed",
"data": [
{
"employeeProjectId": 1,
"projectRoleId": 1,
"employee_project": {
"id": 1,
"status": true,
"type": "backup",
"startDate": "2018-06-28T07:20:36.000Z",
"endDate": "2018-06-29T07:20:39.000Z",
"allocation": 100,
"employeeId": 326,
"projectId": 35,
"employee": {
"firstName": "Asad",
"lastName": "Marfani"
},
"project": {
"name": "RTA"
}
},
"project_role": {
"id": 1,
"role": "front_end_ios"
}
},
{
"employeeProjectId": 1,
"projectRoleId": 2,
"employee_project": {
"id": 1,
"status": true,
"type": "backup",
"startDate": "2018-06-28T07:20:36.000Z",
"endDate": "2018-06-29T07:20:39.000Z",
"allocation": 100,
"employeeId": 326,
"projectId": 35,
"employee": {
"firstName": "Asad",
"lastName": "Marfani"
},
"project": {
"name": "RTA"
}
},
"project_role": {
"id": 2,
"role": "Front End - Android"
}
},
{
"employeeProjectId": 3,
"projectRoleId": 1,
"employee_project": {
"id": 3,
"status": true,
"type": "backup",
"startDate": "2018-06-28T07:47:19.000Z",
"endDate": "2018-06-29T07:47:22.000Z",
"allocation": 50,
"employeeId": 16,
"projectId": 35,
"employee": {
"firstName": "Nosheen",
"lastName": "Sikandar"
},
"project": {
"name": "RTA"
}
},
"project_role": {
"id": 1,
"role": "front_end_ios"
}
},
{
"employeeProjectId": 3,
"projectRoleId": 3,
"employee_project": {
"id": 3,
"status": true,
"type": "backup",
"startDate": "2018-06-28T07:47:19.000Z",
"endDate": "2018-06-29T07:47:22.000Z",
"allocation": 50,
"employeeId": 16,
"projectId": 35,
"employee": {
"firstName": "Nosheen",
"lastName": "Sikandar"
},
"project": {
"name": "RTA"
}
},
"project_role": {
"id": 3,
"role": "Front End - Web"
}
}
]}
const data = obj.data
const res = data.filter(emp => {
return emp.employee_project.id == "1"
}).reduce(item => {
return item
})
console.log(res)