Question

我试图将付款页面添加到我的网站，我从条纹文档中复制了代码，但是当我按“付款”按钮时，什么也没发生。通过调试，返回的令牌为空。问题是，当我尝试在JsFiddle中使用代码时，它可以正常工作，但是当我将其添加到我的应用程序中时，没有响应，控制台为空，因此我在故障排除中迷失了方向。这是html文件：

sudo apk gcc

这是视图：

{% block content %}
<form   method="POST" id="payment-form" >
{% csrf_token %}
  <input type="hidden" name="token" />
    <div class="group">
      <label>
        <span>Card</span>
        <div id="card-element" class="field"></div>
          <div id="card-errors" role="alert"></div>
      </label>
    </div>
    <div class="group">
      <label>
        <span>Name</span>
        <input id="name" name="name" class="field" placeholder="Jane Doe" />
      </label>
    </div>
    <div class="group">
      <label>
        <span>Address</span>
        <input id="address-line1" name="address_line1" class="field" placeholder="77 Winchester Lane" />
      </label>
      <label>
        <span>Address (cont.)</span>
        <input id="address-line2" name="address_line2" class="field" placeholder="" />
      </label>
      <label>
        <span>City</span>
        <input id="address-city" name="address_city" class="field" placeholder="Coachella" />
      </label>
      <label>
        <span>State</span>
        <input id="address-state" name="address_state" class="field" placeholder="CA" />
      </label>
      <label>
        <span>ZIP</span>
        <input id="address-zip" name="address_zip" class="field" placeholder="92236" />
      </label>
      <label>
        <span>Country</span>
        <input id="address-country" name="address_country" class="field" placeholder="United States" />
      </label>
    </div>
    <button type="submit">Pay $25</button>
    <div class="outcome">
      <div class="error"></div>
      <div class="success">
        Success! Your Stripe token is <span class="token"></span>
      </div>
    </div>
  </form>




{% endblock %}

{% block body_scripts %}
<script >
var stripe = Stripe('stripeKeyGoesHere');
var elements = stripe.elements();

var card = elements.create('card', {
  hidePostalCode: true,
  style: {
    base: {
      iconColor: '#666EE8',
      color: '#31325F',
      lineHeight: '40px',
      fontWeight: 300,
      fontFamily: 'Helvetica Neue',
      fontSize: '15px',

      '::placeholder': {
        color: '#CFD7E0',
      },
    },
  }
});
card.mount('#card-element');

function setOutcome(result) {
  var successElement = document.querySelector('.success');
  var errorElement = document.querySelector('.error');
  successElement.classList.remove('visible');
  errorElement.classList.remove('visible');
console.log(result);
  if (result.token) {
    // In this example, we're simply displaying the token
    successElement.querySelector('.token').textContent = result.token.id;
    successElement.classList.add('visible');

    // In a real integration, you'd submit the form with the token to your backend server
    var form = document.querySelector('form');
    form.querySelector('input[name="token"]').setAttribute('value', result.token.id);
    form.submit();
  } else if (result.error) {
    errorElement.textContent = result.error.message;
    errorElement.classList.add('visible');
  }
}

card.on('change', function(event) {
  setOutcome(event);
});

document.querySelector('form').addEventListener('submit', function(e) {
  e.preventDefault();
  var options = {
    name: document.getElementById('name').value,
    address_line1: document.getElementById('address-line1').value,
    address_line2: document.getElementById('address-line2').value,
    address_city: document.getElementById('address-city').value,
    address_state: document.getElementById('address-state').value,
    address_zip: document.getElementById('address-zip').value,
    address_country: document.getElementById('address-country').value,
  };
  stripe.createToken(card, options).then(setOutcome);
});

</script>

Answer 1

当您说单击按钮时没有任何反应时，您是否看到调试（使用浏览器开发工具？）时是否确实发生了表单提交？

还可以在console.log(result)之前尝试在setOutcome函数中添加if (result.token) { }吗？

在调试服务器端代码时，是否可以看到控制器/视图/处理程序，即提交表单时调用payments(request)？您可以检查request.POST词典的内容吗？

想法是检查提交表单时是否实际发出了POST请求（使用浏览器开发工具的客户端），服务器端控制器是否确实接收/处理了该请求以及接收到的POST请求的外观（特别是request.POST词典）。

Answer 2

该问题从未得到解决，因为我没有找到调试方法并找到问题所在，但是Stripe团队帮助我构建了另一种形式，幸运的是，与Django 1.11一起工作，希望它将对运行中的某人有所帮助陷入同一问题：

var stripe = Stripe('stripe key');
var elements = stripe.elements();

var card = elements.create('card', {
  hidePostalCode: true,
  style: {
    base: {
      iconColor: '#666EE8',
      color: '#31325F',
      lineHeight: '40px',
      fontWeight: 300,
      fontFamily: 'Helvetica Neue',
      fontSize: '15px',
      border:'2px',

      '::placeholder': {
        color: '#CFD7E0',
      },
    },
  }
});
card.mount('#card-element');

function setOutcome(result) {
  var successElement = document.querySelector('.success');
  var errorElement = document.querySelector('.error');
  successElement.classList.remove('visible');
  errorElement.classList.remove('visible');

  if (result.token) {
    // In this example, we're simply displaying the token
    successElement.querySelector('.token').textContent = result.token.id;
    successElement.classList.add('visible');

    // In a real integration, you'd submit the form with the token to your backend server
    //var form = document.querySelector('form');
    //form.querySelector('input[name="token"]').setAttribute('value', result.token.id);
    //form.submit();
  } else if (result.error) {
    errorElement.textContent = result.error.message;
    errorElement.classList.add('visible');
  }
}

card.on('change', function(event) {
  setOutcome(event);
});

document.querySelector('form').addEventListener('submit', function(e) {
  e.preventDefault();
  var options = {
    name: document.getElementById('name').value,
    address_line1: document.getElementById('address-line1').value,
    address_line2: document.getElementById('address-line2').value,
    address_city: document.getElementById('address-city').value,
    address_state: document.getElementById('address-state').value,
    address_zip: document.getElementById('address-zip').value,
    address_country: document.getElementById('address-country').value,
  };
  stripe.createToken(card, options).then(setOutcome);
});

条纹付款表格不适用于Django，无法获取令牌

2 个答案: