Question

我有一个非常简单的登录系统，该系统针对3列的MySql数据库进行工作： -用户名 -密码 -LinkToSite

如果登录成功，则在单击“提交”按钮后，应在浏览器中打开相关的LinkToSite（超链接）。我该如何实现？

       <?php
$uname=$_POST['uname'];//username
$password=$_POST['password'];//password 
session_start();
    $con=mysqli_connect("localhost","root","","login");//mysqli("localhost","username of database","password of database","database name")
$result=mysqli_query($con,"SELECT * FROM `login_info` WHERE `uname`='$uname' && `password`='$password'");
$count=mysqli_num_rows($result);
if($count==1)
{
    echo "Login success";
    $_SESSION['log']=1;


}
else
{
    echo "please fill proper details";
    header("refresh:2;url=index.php");// it takes 2 sec to go index page
}
?>

Answer 1

这里不需要任何JS，如果使用JS，则无需刷新页面即可获得结果。但是由于没有得到结果，因此您的查询和代码不合适。以下代码将为您提供所需的结果。

<?php

$uname=$_POST['uname'];//username
$password=$_POST['password'];//password 
//session_start(); //Don't need it here
$con=mysqli_connect("localhost","root","","login");
$result=mysqli_query($con,"SELECT * FROM login_info WHERE uname='".$uname."'"); //Assuming the username to be unique in your database
$count=mysqli_num_rows($result);
if($count==1){
    $row=mysqli_fetch_assoc($result);
    if ($password == $row['password']){
        echo "Login success";
        $_SESSION['log']=1;
        echo "<script>setTimeout(function(){window.location = '".$row['LinkToSite']."' ;}, 3000) ; </script>" ; //It takes 2 seconds to get re-directed to URL saved in database
    }
}
else{
    echo "please fill proper details";
    echo "<script>setTimeout(function(){window.location = 'index.php' ;}, 2000) ; </script>" ; //It takes 2 seconds to get re-directed to index page
}

?>

Answer 2

这将是您必须编写的一些JavaScript。像

if($count==1)
{
    echo "Login success";
    $_SESSION['log']=1;
    echo "<body onpageload=\"dothis();\"></body>

    <script>function dothis(){
    window.location.replace(\"http://stackoverflow.com\");
    }</script>"

}

PHP登录并打开链接

2 个答案: