Question

当用户单击webView中的链接或URL时，我正在尝试启动Safari浏览器。

我有一个带有webView的viewcontroller，可加载请求。在webView上，有一个链接，如果单击该链接，Safari将启动。我已经将webView设置为委托。但这似乎不起作用。它总是将链接加载到嵌入式视图中。我在这里找到的一些答案是旧的目标C代码，它们不起作用。我希望有人能帮忙。

谢谢。

import SafariServices
import UIKit
import WebKit

class AboutViewController: UIViewController, UIWebViewDelegate {

    @IBOutlet weak var spinner: UIActivityIndicatorView!
    @IBOutlet weak var webView: WKWebView!




    override func viewDidLoad() {
        super.viewDidLoad()

        // Start the spinner
        spinner.alpha = 1
        spinner.startAnimating()

        //Set delegate for the webview
        webView.navigationDelegate = self

    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    override func viewWillAppear(_ animated: Bool) {


        let path = Bundle.main.path(forResource: "about", ofType: "html")

        guard path != nil else {  //Guard statement is good to check whether something is true.  So in this case, it reads "confirm if path is not nil else do something else"
            print("Error: Can't find the file")
            return
        }


        //Create a url object from the string path
        let url = URL(fileURLWithPath: path!)
        //Create a request
        let request = URLRequest(url: url)

            //Load the request
            webView.load(request)


    }

    func webView(_: WKWebView, shouldStartLoadWith: URLRequest, navigationType: WKNavigationType ) -> Bool {

    if navigationType == WKNavigationType.linkActivated {
        UIApplication.shared.open(shouldStartLoadWith.url!, options: [:], completionHandler: nil)

        return false
    }

    return true
   }

}

Answer 1

我正在使用此线程（WKWebView open links from certain domain in safari）使其正常工作。

这是答案：

import SafariServices
import UIKit
import WebKit

class AboutViewController: UIViewController, WKNavigationDelegate {

@IBOutlet weak var spinner: UIActivityIndicatorView!
@IBOutlet weak var webView: WKWebView!


override func viewDidLoad() {
    super.viewDidLoad()

    // Start the spinner
    spinner.alpha = 1
    spinner.startAnimating()


    let path = Bundle.main.path(forResource: "about", ofType: "html")

    guard path != nil else {  //Guard statement is good to check whether something is true.  So in this case, it reads "confirm if path is not nil else do something else"
        print("Error: Can't find the file")
        return
    }

    //Create a url object from that string path
    let url = URL(fileURLWithPath: path!)






    //Set delegate for the webview
    webView.navigationDelegate = self

     //Load the request
    webView.load(URLRequest(url: url))

}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

override func viewWillAppear(_ animated: Bool) {



}







func webView(_ webView: WKWebView,  decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
    if navigationAction.navigationType == .linkActivated  {
        if let url = navigationAction.request.url,
            let host = url.host, !host.hasPrefix("www.google.com"),
            UIApplication.shared.canOpenURL(url) {
            UIApplication.shared.open(url)
            //print(url)
           // print("Redirected to browser. No need to open it locally")
            decisionHandler(.cancel)
        } else {
           // print("Open it locally")
            decisionHandler(.allow)
        }
    } else {
        //print("not a user click")

        decisionHandler(.allow)
    }
}


func webView(_ webView: WKWebView, didFinish navigation: WKNavigation!) {
    spinner.stopAnimating()
    spinner.alpha = 0

}

}

当用户单击webView中的URL或链接时启动Safari

1 个答案: