Question

我看到了一些与此问题类似的帖子。我已经尝试过使每个人适应自己的需求，但是我提出了一些建议。希望有人可以在此mysql语句中提供一些帮助：

父表：客户端

  `id` int(11) NOT NULL AUTO_INCREMENT,

子表：约会

CREATE TABLE `appointment` (
  `aptID` int(11) NOT NULL AUTO_INCREMENT,
  `start_time` time DEFAULT NULL,
  `date` date DEFAULT NULL,
  `id` int(11) DEFAULT NULL,
  `reason` enum('Assessment','Follow-up') DEFAULT NULL,
  `outcome` enum('Show','No Show') DEFAULT NULL,
  `last30` int(5) DEFAULT NULL,
  PRIMARY KEY (`aptID`),
  KEY `fk_appointment_client1_idx` (`id`),
  CONSTRAINT `fk_appointment_client1` FOREIGN KEY (`id`) REFERENCES `client` (`id`) ON DELETE CASCADE ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=31 DEFAULT CHARSET=utf8;

我需要以下报告：

1）最近30天内的约会次数 2）365天的约会次数 3）约会次数 4）最近30天内错过的约会次数

我创建了一个视图，该视图除了最后一个（错过的约会）以外，还为我提供所有其他内容，但是我不知道如何合并错过的约会：

CREATE VIEW `total`
AS SELECT
   id AS id,
   name AS name,
    count(`C1`) AS `Last30days`,
    count(.`C2`) AS `Last365Days`,
    count(`C3`)  AS `Alltime`

FROM (select
client.id AS id,
client.name AS name,
(CASE WHEN DATEDIFF(CURDATE(), date) <= 30 THEN NULL end) AS `C1`,
(CASE WHEN DATEDIFF(CURDATE(), date) <= 365 THEN NULL end) AS `C2`,
(select count(*) from appointment where id=client.id) as `C3`

from 
(client left join appointment on((client.id = appointment.id))))
group by `total`.`id`;

问题1 ：如何将过去30天内错过的约会纳入此视图？错过的约会将在过去30天内作为结果变量为“未显示”的约会进行操作。我认为可以通过添加以下两行来实现：

count(`C4`) AS `Missed30`

(CASE WHEN DATEDIFF(CURDATE(), date) <= 365 where outcome = 'No Show' THEN NULL end)  AS `C4`

问题2 ：如何将整个语句转换为插入语句，以定期从视图捕获数据。这将进入一个名为apt_total的表。我尝试了一些变体，但是没有什么能接近工作的。

非常感谢您的协助。

Answer 1

您要使用SUM（IF（）），如果条件匹配，则将SUM为1。见下文。

SELECT
  id,
  name,
  SUM(IF(DATEDIFF(CURDATE(), date) <= 30, 1, 0)) AS Last30Days,
  SUM(IF(DATEDIFF(CURDATE(), date) <= 365, 1, 0)) AS Last365Days,
  COUNT(*) AS AllTime,
  SUM(IF(DATEDIFF(CURDATE(), date) <= 30 AND outcome = 'No Show', 1, 0)) AS NoShow
 FROM
  appointments AS a
  INNER JOIN clients AS c ON a.id = c.id
 GROUP BY
  id

这应该为您提供所需的号码。如果要将SELECT转换为INSERT，则可以执行以下操作。

INSERT INTO apt_total
SELECT
  id,
  name,
  SUM(IF(DATEDIFF(CURDATE(), date) <= 30, 1, 0)) AS Last30Days,
  SUM(IF(DATEDIFF(CURDATE(), date) <= 365, 1, 0)) AS Last365Days,
  COUNT(*) AS AllTime,
  SUM(IF(DATEDIFF(CURDATE(), date) <= 30 AND outcome = 'No Show', 1, 0)) AS NoShow
 FROM
  appointments AS a
  INNER JOIN clients AS c ON a.id = c.id
 GROUP BY
  id

您需要确保列相同，否则将INSERT INTO apt_total更改为以下内容：

INSERT INTO apt_total (col1, col2, col3.....)

最近30天内错过约会的MYSQL声明

1 个答案: