Question

我已经开始学习GraphQL了一个星期，而我最大的挑战是处理邮政数据。我读过，这全都与突变有关，但是我不正确。我只是想将Survivor（我的模型）对象发布到我的数据库中
这是代码：这是应用程序的架构

import graphene
from graphene import relay, ObjectType

from graphene_django.types import DjangoObjectType
from graphene_django.filter import DjangoFilterConnectionField

from .models import Survivor

class SurvivorNode(DjangoObjectType):
    class Meta:
        model = Survivor
        filter_fields = ['name']
        interfaces = (relay.Node, )



class SurvivorInput(graphene.InputObjectType):

    name = graphene.String(required=True)
    age = graphene.Int(required=True)


class AddSurvival(graphene.Mutation):
    class Arguments:
        survivor_data = SurvivorInput()

    survivor = graphene.Field(SurvivorNode)

    @staticmethod
    def mutate(root,info,survivor_data):
        survivor=Survivor(
            name = survivor_data.name,
            age = survivor_data.age
        )

        return AddSurvival(survivor = survivor)



class Query(object):
    all_survivors = DjangoFilterConnectionField(SurvivorNode)
    survivor = relay.Node.Field(SurvivorNode)

请问我怎么了？

那我该怎么办？

Answer 1

在mutate方法中，您需要更改

survivor=Survivor(
            name = survivor_data.name,
            age = survivor_data.age
        )

对此

survivor=Survivor.objects.create(
            name = survivor_data.name,
            age = survivor_data.age
        )

因为您要创建Survivor类型的新对象。

石墨烯突变Tultorial不起作用

1 个答案: